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lora16 [44]
3 years ago
6

Need help will give brainliest easy math

Mathematics
2 answers:
hoa [83]3 years ago
7 0
-1k is the answer to this question
natka813 [3]3 years ago
5 0

Answer:

-1k?

Step-by-step explanation:

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(2^8 ⋅ 3^−5 ⋅ 6^0)^−2 ⋅ 3 to the power of negative 2 over 2 to the power of 3, whole to the power of 4 ⋅ 2^28 (5 points) Write y
mihalych1998 [28]
Start by looking at simplifying the smaller problems 

anything to the power zero is 16^0 = 1

next apply the power of a power rule... multiply the powers 

(2^8\times 3^{-5} \times 1 )^{-2} = 2^{8\times -2}\times 3^{-5 \times -2}

which becomes 

2^{-16}\times 3^{10}

4 0
3 years ago
19. Parkash had just enough money to buy 100 pencils. However, he bought only 70 pencils and had $4.50 left. What was the cost o
prisoha [69]

Answer:

since the unknown amount can buy 100 pencils

he bought 70 pencils

therefore $4.50 can buy 30 pencils

so 1 pencils cost $4.50 /30=0.15

7 0
2 years ago
Read 2 more answers
I’LL MARK BRAINLEST! :)
dem82 [27]

Answer:

9.1

Step-by-step explanation:

I think this because it is 9 boxes away from the other points, plus it sloped a bit...

7 0
3 years ago
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Question 4 (10 points)
Bess [88]

Answer:

kenneth-privatetutoring.youcanbook.me

Step-by-step explanation:

3 0
3 years ago
Stuck, help please !
Olin [163]

Use the fundamental trigonometric equation

\sin^2(x) + \cos^2(x) = 1 \implies \sin^2(x) = 1-\cos^2(x)

To rewrite the equation as

1-\cos^2(x) = 1-\cos(x)

Subtract 1 from both sides:

-\cos^2(x) = -\cos(x)

Add \cos^2(x) to both sides:

\cos^2(x) - \cos(x) = 0 \iff \cos(x)\left(\cos(x)-1\right)=0

A multipication is zero if and only if one of the factors is zero. So, the solutions are given by

\cos(x)=0 \iff x=\dfrac{\pi}{2}+k\pi,\quad k \in \mathbb{Z}

or

\cos(x)-1=0 \iff \cos(x)=1 \iff x=2k\pi,\quad k \in \mathbb{Z}

5 0
4 years ago
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