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3 years ago

The distance light travels in one year is approximately 5,870,000,000,000 miles. The distance light travels in 100 years is:

Mathematics

1 answer:

rewona [7]3 years ago

5 0

The answer is 5.87x10^14 this is because when you multiply 5870000000000 times 100 you get 5.87x10^14

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A brand of uncooked spaghetti comes in a box that is a rectangular prism with a length of 10 inches, a

tankabanditka [31]

Answer:

Surface area means all of the outside areas, kind of like when you wrap a present.

Step-by-step explanation:

1st draw the box and find the area of the top and the bottom of the figure

10 x 3 = 30 for the top and 30 for the bottom, so 60 for both.

2nd find the area of two opposite sides:

10x 4.5 = 45 for one side and 45 for the other side, which is 90 for both

3rd find the area of the last two opposite sides:

3 x 4.5 = 13.5 for one side and 13.5 for the other side, so 27 for both.

4th: now add all those sides 60 + 90 + 27 = 177 inches squared.

8 0

3 years ago

How to find the inter quartile range of these <br><br> 1,1,1,2,2,3,3,4,5

Anna007 [38]

Answer:

2.5

Step-by-step explanation:

1st Quartile (Q1): 1

2nd Quartile (Q2): 2

3rd Quartile (Q3): 3.5

IQR = Q3 - Q1 = 3.5 - 1 = 2.5

5 0

3 years ago

Select all the equations where z = 5 is a solution

Morgarella [4.7K]

Answer: There isn't any pictures what do you want us to answer???

7 0

3 years ago

Find the mean of this set of numbers. 9, –6, –8, 11, –4, 10

Karolina [17]

The answer is A. You add all the numbers together and get 12 then you divide it by 6 and get 2

7 0

3 years ago

find the equation of the line which passes through the point (-5,5) and is parallel to the given line. express your answer in sl

Softa [21]

The given equation of a line is:

$7y-14=-3(5-x)$

It is required to find the equation of a line that is parallel to this line and passes through the point (-5,5).

Recall that the equation of a line in point-slope form is given as:

$y-y_1=m(x-x_1)$

Where m is the slope of the line, and the line passes through the point (x₁,y₁).

Rewrite the given equation in the point-slope form:

$\begin{gathered} 7y-14=-3(5-x) \\ Distribute\text{ -1 into the parentheses in the right-hand side:} \\ \Rightarrow7y-14=3(-5+x) \\ \text{Rewrite the expression in the parentheses using the co}mmutative\text{ property of addition:} \\ \Rightarrow7y-14=3(x-5) \\ \text{Divide both sides of the equation by 7:} \\ \Rightarrow y-2=\frac{3}{7}(x-5) \end{gathered}$

Compare this equation with the standard point-slope form written above, it can be seen that the slope of the line is 3/7.

Recall that the slopes of parallel lines are the same or equal<em>.</em>

It follows that the slope of the required parallel line is also 3/7.

Substitute m=3/7 and the point (x₁,y₁)=(-5,5) into the point-slope form of the equation of a line:

$y-5=\frac{3}{7}(x-(-5))$

Rewrite the equation in the slope-intercept form and simplify as required:

$\begin{gathered} \Rightarrow y-5=\frac{3}{7}(x+5) \\ \Rightarrow y-5=\frac{3}{7}x+\frac{15}{7} \\ \Rightarrow y=\frac{3}{7}x+\frac{15}{7}+5 \\ \Rightarrow y=\frac{3}{7}x+\frac{50}{7} \end{gathered}$

The required equation of the line is y=3/7 x + 50/7.

5 0

1 year ago