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astraxan [27]
3 years ago
6

Tina is saving to buy a notebook computer. She has two options. The first option is to put200$ away initally and save 10$every m

onth. Thge second option is to put 100$ away and save 30$ every month. After how many months would Tina save the same amount using either option? How much would she save at the time?
Mathematics
1 answer:
Archy [21]3 years ago
5 0

about 6 months as the number will meet


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Plz help with this question​
Dennis_Churaev [7]

Answer:

y = -2x+4

Step-by-step explanation:

the equation of the line there is: y = -2x+8

The parallel line to this one should have the same slope as the first one(-2x)

Parallel lines always have the same slopes

7 0
3 years ago
Which of the following equations have exactly one solution?
BARSIC [14]

Answer:

2, 3, 4 all have one solution.

Step-by-step explanation:

The first one has no solution.

The second one has a solution of -65/68.

The third one has a solution of 5.

The fourth one has a solution of 13/2.

Hope this helps!!

Let me know if I'm wrong...

3 0
4 years ago
Help me please, please please
rjkz [21]

Answer:

I can't see the question

Step-by-step explanation:

Heelp me see by typing it up

5 0
3 years ago
Will give brainlist
Vladimir [108]

Answer:

y=24  x=33

Step-by-step explanation:

Example: ⇒

y

=

k

x

to find k use the given condition

y

=

−

24

when

x

=

8

y

=

k

x

⇒

k

=

y

x

=

−

24

8

=

−

3

equation is

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

∣

∣

∣

2

2

y

=

−

3

x

2

2

∣

∣

∣

−−−−−−−−−−−−−−

when

x

=

10

then

y

=

−

3

×

10

=

−

30

8 0
3 years ago
Simplify the given expression. Assume that no variable equals 0. (14x20y10 / 28x12y14)4
liq [111]

Answer:

\frac{1}{2^{4}*14^{3} *x^{28}*y^{46}}

Step-by-step explanation:

To simplify the expression \frac{14x^{20}y^{10}}{(2*14*x^{12} y^{14} )^{4}} first we need to raise every member of the denominator to the given exponent, number 4

Remember that (x^{b} )^{c} =z^{b*c} where 'a' and 'b are natural numbers (any numbers you want

\frac{14x^{20}*y^{10}}{2^{4}*14^{4}*x^{48}*y^{56}}

Where we can make some operations, remember that \frac{x^{a} }{x^{c} }=x^{a-c}

\frac{1}{2^{4}*14^{3} *x^{28}*y^{46}}

We have assumed that nor x, nor y equals 0 in any moment, since if that would happen, we ca not simplify anything bacause error math 0/0.

7 0
4 years ago
Read 2 more answers
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