Ask question

Ask question

All categories

3 years ago

9

Chau bought 48 ounces of nuts at the store. How much is this in pounds? Use the table below. Include the correct unit in your an

swer

1 answer:

slavikrds [6]3 years ago

7 0

48 ounces is equivalent to 3 pounds (lbs)

You might be interested in

What is the relationship between a rotation and a rigid motion?

Papessa [141]

A rotation is a rigid motion

5 0

3 years ago

Which shows a correct order to solve this story problem? Kent and Curtis went to the state fair. They had to pay a total of $7.1

KiRa [710]

The problem is asking how much each person will need to pay. Simplifying the problem into an equation with variables (an algorithm) will greatly help you solve it:

S = Sales Tax = $ 7.18 per any purchase
A = Admission Ticket = $ 22.50 entry price for one person (no tax applied)
F = Food = $ 35.50 purchases for two people

We know the cost for one person was: (22.50) + [(35.50/2) + 7.18] =
$ 47.43 per person. Now we can check each method and see which one is the correct algorithm:

Method A)
[2A + (F + 2S)] / 2 = [ (2)(22.50) + [35.50 + (2)(7.18)] ]/ 2 = $47.43
Method A is the correct answer

Method B)
[(2A + (1/2)F + 2S) /2 = [(2)(22.50) + 35.50(1/2) + (2)7.18] / 2 = $38.55
Wrong answer. This method is incorrect because the tax for both tickets bought are not being used in the equation.

Method C)
[(A + F) / 2 ]+ S = [(22.50 + 35.50) / 2 ] + 7.18 = $35.93
Wrong answer. Incorrect Method. The food cost is being reduced to the cost of one person but admission price is set for two people.

6 0

3 years ago

Write an expression that is equal to 10 using only four 2s and any number of math symbols

diamong [38]

$(4 \times 2) + 2$

8 0

3 years ago

Read 2 more answers

I bought 8 shirts that cost an average of $27. My sister then added 3 shirts. The 11 shirts had a mean cost of 28.50. How much d

Montano1993 [528]

It cost 50 cent each first i subtracted 27 from 28.50 and it gave me 1.50 de i divided 1.50 by 3 and it gave 50 cent

8 0

3 years ago

A license plate consists of 2 letters followed by 3 digits. How many license plates are possible if the 1st digit cannot be 0, a

zloy xaker [14]

There are 608400 plates are possible.

If the first is A, we have 26 possibilities:

AA, AB, AC,AD,AE ...................................... AW, AX, AY, AZ.

If the first is B, we have 26 possibilities:

BA, BB, BC, BD, BE .........................................BW, BX,BY,BZ

And so on for every letter of the alphabet.

There are 26 choices for the first letter and 26 choices for the second letter. The number of different combinations of 2 letters is:

26×26=676

The same applies for the three digits.

There are 9 choices for the first as first digit cannot be 0

10 for the second,

10 for the third

9×10×10=900

So for a license plate which has 2 letters and 3 digits, there are:

676 × 900 = 608400 possibilities

To learn more about calculating possibilities from the given link

brainly.com/question/4658834

#SPJ4

8 0

2 years ago