We'll check if they're orthogonal:
u*v=0
(6,-2)*(8,24)=0
6*8+(-2)*24=0
48-48=0
0=0
they are orthogonal vectors
<h3>The ladder will reach a height of 11.8 feet up the wall</h3>
<em><u>Solution:</u></em>
The ladder, wall and base of the ladder from wall forms a right angled triangle
Length of ladder forms the hypotenuse
Length of ladder = 12 foot
base of the ladder from wall = 2 feet
<em><u>To find: height of wall</u></em>
By pythagoras theorem.

Where,
"c" is the Length of ladder
"a" is the base of the ladder from wall
"b" is the height of wall
Substituting the values,

Thus, the ladder will reach a height of 11.8 feet on wall
Answer:
Ok I don't know waht you mean but the answer is
Step-by-step explanation:
Answer:
x=3/2±(√11)2
x=1.5+1.65831i
x=1.5−1.65831i
Find the Solution for
2x^22−6x+10=0
using the Quadratic Formula where
a = 2, b = -6, and c = 10
x=(−b±√(b^2−4ac))/2a
x=(−(−6)±√((−6)2−4(2)(10)))2(2)
x=(6±√(36−80))/4
x=(6±√−44)/4
The discriminant b^2−4ac<0
so, there are two complex roots.
Simplify the Radical:
x=(6±2√11 i)/4
x=6/4±(2√11 i)4
Simplify fractions and/or signs:
x=3/2±(√11)2
which becomes
x=1.5+1.65831i
x=1.5−1.65831i
Answer:
The first option is the correct one, the area of the shaded portion of the circle is
[/tex](5 \pi -11.6)ft^2[/tex]
Step-by-step explanation:
Let us first consider the triangle + the shadow.
The full area of the circle is the radius squared times pi, so
A=
Since
, the area of the triangle + the shaded area is one fifth of the area of the whole circle, thus

If we want to know the area of the shaded part of the circle, we must subtract the area of the triangle from
.
The area of the triangle is given by

Thus the area of the shaded portion of the circle is
