Answer:
A=132
Step-by-step explanation:
A=ah+bh+ch+1
2﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4=3·10+4·10+5·10+1
2·﹣34+2·(3·4)2+2·(3·5)2﹣44+2·(4·5)2﹣54=132
Answer:
1296 orders
Step-by-step explanation:
There is a pattern to his orders.
First, he starts with 6.
Second, he made 36.
Third, he made 216.
From here, the pattern can be identified. And, you can extend it further.
Pattern - x · 6
x = the orders.
6, 36, 216
6 (September) × 6 = 36 (October)
36 × 6 = 216 (November)
216 × 6 = 1296 (December)
With 5 elements in A={20,1,6,10,11}, there are 2^5=32 possible subsets, including
the null set, and A itself.
Any subset that is identical to A is NOT a proper subset.
Therefore there are 31 proper subsets, plus the subset {20,1,6,10,11}.
The subsets are:
null set {} (has no elements) ........total 1
{20},{1},{6},{10},{11}.......................total 5
{20,1},{20,6}...{10,11}.....................total 10
{20,1,6},{20,1,10},...{6,10,11}.........total 10
{20,1,6,10}...{1,6,10,11}.................total 5
{20,1,6,10,11}.................................total 1
Altogether 32 subsets.
