Which is the correct number of moles of nitrogen monoxide that is produced from 13.2 moles of oxygen gas in the presence of exce ss ammonia (NH3)?
1 answer:
Answer:
10.56 moles of NO will be produced
Explanation:
The balanced reaction of ammonia, NH₃ with oxygen, O₂ is:
4NH₃ + 5O₂ → 4NO + 6H₂O
<em>Where 5 moles of oxygen react with an excess of ammonia to produce 4 moles of nitrogen monoxude.</em>
<em />
If 13.2 moles of O₂ react:
13.2 mol O₂ * (4 mol NO / 5 mol O₂) =
<h3>10.56 moles of NO will be produced</h3>
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