Answer:
–1647.45 J
Explanation:
From the question given above, the following data were obtained:
Mass (M) = 112.5 g
Initial temperature (T₁) = 12.5 °C
Final temperature (T₂) = 9°C
Specific heat capacity (C) = 4.184 J/g°C
Heat (Q) absorbed =?
Next, we shall determine the change in temperature. This can be obtained as follow:
Initial temperature (T₁) = 12.5 °C
Final temperature (T₂) = 9°C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 9 – 12.5
ΔT = –3.5 °C
Finally, we shall determine the heat absorbed. This can be obtained as follow:
Mass (M) = 112.5 g
Change in temperature (ΔT) = –3.5 °C
Specific heat capacity (C) = 4.184 J/g°C
Heat (Q) absorbed =?
Q = MCΔT
Q = 112.5 × 4.184 × –3.5
Q = –1647.45 J
The correct answer is: [A]: " <span>∆G=∆H-T∆S ".
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Answer
C6H807 = 192.124 g/mol
n = m/M
n = 0.119 mol
Explanation:
to calculate amount in moles you need to find the molar mass of citric acid then divide the mass of the acid with the molar mass
Answer:
in illustration 1
the mother told her son not to play with the boy having cough because it is a transferable disease which could cause him also to get sick and would get cough.
while in
illustration 2
the mother let the boy play with the boy having asthma because it is not a transferable disease which wold not affect him or any one else.
Explanation:
this is the reason
Answer:
a mass is constant during -free-weight training,a greater impulse will result in greater velocity.therefore as a generation of force greater than weight of the resistance increases.
