Exponential model is y=Ae^(kt)
Assume initial start is 2005, time = 0, so y = 18000e^(kt)
45000 = 18000*e^(k5)
solve for k, approx 0.1832
y = 18000*e^(1.832) = 112,435, approximately
Well, what you can do is divide both of them by $1544.40, and then figure out how many their were that day
9514 1404 393
Answer:
61.4
Step-by-step explanation:
The length of two semicircles of diameter 10 is the circumference of a circle of that diameter:
C = πd = 10π ≈ 31.4
The perimeter includes that length plus the lengths of two straight sides that are 15 units each.
P = 31.4 + 2×15
P = 61.4 . . . . units
<u>Answer:</u>
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<u>Step-by-step explanation:</u>
From the graph, we can see that y = -1 when x = 0.
So to check whether which of the given options is the equation of the given graph, we will set our calculator to the radian mode and then plug the value of x as 0.
1. y = cos(x + pi/2) = cos(0 + pi/2) = 0
2. y = cos(x+2pi) = cos(0+2pi) = 1
3. y = cos(x+pi/3) = cos(0+pi/3) = 1/2 = 0.5
4. y = cos(x+pi) = cos(0+pi) = -1
Therefore, the equation of this graph is y = cos(x+pi) = cos(0+pi) = -1.
Answer:
8(x) = 56 (x = 7) (x) + 5 3/4 = 8 3/4 (x = 3) x/2 = 3.5 (x = 7) Neither x - 2.56 = 0.44 (x = 3)
Step-by-step explanation: