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PSYCHO15rus [73]
3 years ago
14

There are 48 female performers in a dance recital. The ratio of men to women is 5:6. How many men are in the dance recital?

Mathematics
1 answer:
Rainbow [258]3 years ago
5 0

Since you said men to women, there are 5 men in the dance recital and 6 women in the dance recital.

1. Look how the problem states. Ex: Ratio of men to women.

2. Look at the ratio. 5:48.

3. We know that there are 48 female performers at the dance recital.

So, there are 5 men at the dance recital.

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The image shows the dimensions of a pool.
Juliette [100K]
<h3>Answer:  D) 198 square meters</h3>

======================================================

Explanation:

Extend the side that's 9.5 meters long out to the left so that you form a trapezoid on top and a rectangle underneath. The side we extended is now 5+9.5 = 14.5 meters long.

Let

  • A = area of the trapezoid up top
  • B = area of the rectangle underneath

The goal is to find A+B

The trapezoid has the parallel sides of 14.5 and 10 meters. The height of the trapezoid is 28-20 = 8 meters. So we can say

Area of trapezoid = height*(base1+base2)/2

A = h*(b1+b2)/2

A = 8*(14.5+10)/2

A = 98

The rectangle has area of B = length*width = 5*20 = 100 square meters

Therefore,

total area = A+B = 98+100 = 198 square meters.

8 0
3 years ago
Scatterplot A<br> correlation coefficient
Yuri [45]

Well I sent you sum pictures

6 0
3 years ago
It has been found that women are excluded from social events with coworkers. One study at Company X, found that women only recei
Natasha2012 [34]

Answer:

Option C is correct.

The p-value in this case is the probability of getting data like that observed or more extreme (i.e., getting an observed invitation rate of 33% or higher) assuming that;

The social strategies did not increase the rate of invitations for female colleagues.

Step-by-step explanation:

The p-value is actually defined as the probability of obtaining results as extreme as the observed results in the statistical analysis provided that the null hypothesis is true.

The standing condition for the p-value definition is the assumption that the null hypothesis is true, then it is the probability of getting the extreme result (usually not due to just random chance), that is usually observed, being tested for and contained in the alternative hypothesis.

Normally, in hypothesis testing, especially one comparing two sets of data, the null hypothesis plays the devil's advocate and usually takes the form of the opposite of the theory to be tested. It usually contains the signs =, ≤ and ≥ depending on the directions of the test. It usually maintains that, with random chance responsible for the outcome or results of any experimental study/hypothesis testing, its statement is true.

The alternative hypothesis usually confirms the theory being tested by the experimental setup. It usually contains the signs ≠, < and > depending on the directions of the test. It usually maintains that significant factors other than random chance, affect the outcome or results of the experimental study/hypothesis testing and result in its own statement.

Since this test aimed to test whether the rate of invitation of women to outside work events after using the social strategies, the null hypothesis for the question would be that there is no significant difference in the rate of invitation of the women after using the social strategies while the alternative hypothesis would be that the social strategies worked and the rate invitation of women to outside of work events increased.

So, the null hypothesis that we need to assume was true in the p-value definition is that; the social strategies did not increase the rate of invitations for female colleagues.

This is option C!

Hope this Helps!!!

8 0
3 years ago
5+1/2(14b-8)=-6 5+__b-4=-6 7b+__=-6 7b=__ b=__ ANSWERS 7-7-1 1
Lunna [17]

Answer:

7, 1, -7, -1.

Step-by-step explanation:

5+1/2(14b-8) = -6

5 + 7b - 4 = -6

7b + 1 = -6

7b = -7

b = -1

So, your answer will be 7, 1, -7, -1.

Hope this helps!

3 0
3 years ago
Hunter and Brian are creating a poster for a project and they need to combine two different size boards to create their project.
shepuryov [24]

Answer:

<em>The maximum area of the second board must be (5x^2+3x-6) square inches.</em>

Step-by-step explanation:

The total area of two different size boards cannot exceed (7x^2-6x+2) square inches.

The area of one board is  (2x^2-9x+8) square inches.

Suppose, the area of the second board is  y square inches.

That means......

y+(2x^2-9x+8)\leq 7x^2-6x+2\\ \\ y\leq (7x^2-6x+2)-(2x^2-9x+8)\\ \\y \leq 7x^2-6x+2-2x^2+9x-8\\ \\ y\leq 5x^2+3x-6

So, the maximum area of the second board must be (5x^2+3x-6) square inches.

7 0
3 years ago
Read 2 more answers
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