F(x)=x^2+2x+1 & g(x)=3(x+1)^2
now, f(x)+g(x)
=x^2+2x+1+3(x+1)^2
=x^2+2x+1+3(x^2+2x+1)
=x^2+2x+1+3x^2+6x+3
=4x^2+8x+4<===answer(c)
next:
f(x)=x^2-1 & g(x)=x+3
now, f(g(x))=(x+3)^ -1
=x^2+6x+9-1
=x^2+6x+8<====answer(b)
i solve two of ur problems.
now try the 3rd one that is similar to no. 1
and try the last two urself.
(b)
i do not know number 2 sorry
3. (A)
hope it helps have a great day :D
686 barrels left. If I'm not mistaken this should just be simple subtraction
Diagonal of a rectangle formula:
Diagonal = √l² + w²
Diagonal = √10² + 8²
Diagonal = √100 + 64
Diagonal = √164
Diagonal = 12.806 feet.
Or you can use the pythagorean theorem. The diagonal of a rectangle is the hypotenuse of a triangle.
a²
+ b² = c² ; where a and b represents the lengths of the triangle and c
is the hypothenuse. In this case, the lengths are 10 ft and 8ft.
10² + 8² = 100 + 64 = 164 ; This represents c².
c = √c² = √164 = 12.806 ft
A=s^2
A=6.3^2
(A=6.3x6.3)
And your answer would be:
A=39.69cm^2
