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Pepsi [2]
3 years ago
10

Identify the molecule that is a carbohydrate.

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
8 0

Answer:

(B)table sugar

balu736 [363]3 years ago
4 0

It’s all of them except C. Yep totally. Not going back. I’m right. Ok maybe I’m going back. Ok maybe it may not be A. Or B. Or D. It may be C though

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3x+2y=15<br> 4x-5y=-3<br> What is the following system of equations
laila [671]

Answer:

x=3,y=3

Step-by-step explanation:

8 0
3 years ago
I need help with this
Nostrana [21]

Answer:

28 times

Step-by-step explanation:

2.8414 x 10^9 ÷ 1.0127 x 10^8

(2.8414 ÷ 1.0127) · (10^9 ÷ 10^8)

2.8 x 10

28

4 0
3 years ago
Help Plz. FAST! 12 ounces for $5.30. Explain how you got your answer
Agata [3.3K]
$2.25 an ounce for unit price
5 0
3 years ago
1. Calculate the rate of change for the following data:
expeople1 [14]

the slope goes by several names

• average rate of change

• rate of change

• deltaY over deltaX

• Δy over Δx

• rise over run

• gradient

• constant of proportionality

however, is the same cat wearing different costumes.

well, to get it all we need is two points, say hmmm let's use (-1 , -7) and (7 , 25)

(\stackrel{x_1}{-1}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{7}~,~\stackrel{y_2}{25}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{25}-\stackrel{y1}{(-7)}}}{\underset{run} {\underset{x_2}{7}-\underset{x_1}{(-1)}}}\implies \cfrac{25+7}{7+1}\implies \cfrac{32}{8}\implies 4

4 0
3 years ago
5. In the diagram shown below, BC is drawn tangent
Tatiana [17]

9514 1404 393

Answer:

 (2)  72°

Step-by-step explanation:

In this geometry, the angle at the tangent is half the measure of the intercepted arc.

  ∠CBD = (arc BD)/2 = 144°/2

  ∠CBD = 72°

__

<em>Additional comment</em>

Consider a point X anywhere on long arc BD. The inscribed angle at X will have half the measure of short arc BD, so will be 144°/2 = 72°. This is true regardless of the position of X on long arc BD. Now, consider that X might be arbitrarily close to point B. The angle at X is still 72°.

As X approaches B, the chord XB approaches a tangent to the circle at B. Effectively, this tangent geometry is a limiting case of inscribed angle geometry.

6 0
3 years ago
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