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3 years ago

15

Can anyone Plz help me in this question (see the attachment) Fast Plz tomorrow is my exam....

1 answer:

vaieri [72.5K]3 years ago

7 0

Answer:

I hope this helps. When you're drawing yours, make this widths of the bars the same. Leave a gap before drawing your bars.

Please give brainliest.

I've you don't understand something, please comment

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Cos(x)= sin(35) what does x =?

mylen [45]

Here,

cos(x) = sin(35)
cos(x) = cos(90-55)
cos(x) = cos(55)
x = 55

3 0

3 years ago

Use decimals and fractions in the same equation showing the Commutative Property. Repeat for the Associative Property.

Anna71 [15]

For Commutative Property of Addition

Let us take a decimal number $2.14$ and a fraction $\frac{5}{20}$

Now, according to the Commutative property of Addition:

For any two numbers $a$ and $b$ :

$a+b = b+a$

So, for $2.14$ and $\frac{5}{20}$

Let us add

$2.14+\frac{5}{20} = \frac{214}{100} +\frac{5}{20}$

$=\frac{214}{100} + \frac{5 \times 5}{20 \times 5} \\ \\=\frac{214}{100} + \frac{25}{100} \\ \\= 2.14 + 0.25 \\ \\ = 2.39$

Also,

$\frac{5}{20} + 2.14 = \frac{5}{20} + \frac{214}{100}$

$= \frac{5 \times 5}{20 \times 5} +\frac{214}{100} \\ \\= \frac{25}{100} + \frac{214}{100} \\ \\= 0.25 + 2.14 \\ \\ = 2.39$

Therefore, $2.14+\frac{5}{20} = \frac{5}{20} + 2.14$

Hence, Commutative Property of Addition is satisfied.

For Associated Property of Addition

Let us take two same decimal numbers $2.14$ , $7.25$ and a fraction $\frac{5}{20}$

Now, according to the Associated property of Addition:

For any three numbers $a$ , $b$ and $c$

$a + (b+c) =(a+b) + c$

So, for $2.14$ , $7.25$ and $\frac{5}{20}$

The Left hand side:

$a + (b+c)$

$2.14 + (7.25 + \frac{5}{20}) = 2.14 + (\frac{725}{100} + \frac{5 \times 5}{20\times 5})$

$= 2.14 + (\frac{725}{100} + \frac{25 }{100})$

$= 2.14 + (\frac{750}{100} )$

$= \frac{214}{100} + \frac{750}{100}$

$= \frac{964}{100}$

$=9.64$

The Right hand side:

$(a + b )+c$

$(2.14 + 7.25 )+ \frac{5}{20}= ( 9.39 ) + \frac{5 }{20}$

$= 9.39 + \frac{5 \times 5 }{20 \times 5}$

$= 9.39 + \frac{25}{100}$

$= 9.39 + 0.25$

$= 9.64$

Thus,

$(2.14 + (7.25 + \frac{5}{20} )= (2.14 + 7.25 )+ \frac{5}{20}$

Therefore, $2.14+\frac{5}{20} = \frac{5}{20} + 2.14$

Hence, Associative Property of Addition is satisfied.

8 0

3 years ago

Volume of right trapezoid cylindar whole bases are B 16m, b 8m, height is 4m and length is 32m

viktelen [127]

Answer:

$volume = 1536 m^3$

Step-by-step explanation:

given data;

B = 16m

b =8 m

height H = 4 m

length L = 32 m

volume of any right cylinder = (Area of bottom) \times (length)

Volume = A* L

The area of a trapezoid is

$A=\frac{1}{2} H*(b+B)$

$A =\frac{1}{2} 4*(8+16)$

$A = 48 m^2$

therefore volume is given as

volume = 48*32

$volume = 1536 m^3$

6 0

3 years ago

11. A roofer calculates his bid price using the formula P = 1.85s + 4.2f, where s is the area of the roof in square feet and f i

storchak [24]

Replace f with 190, replace P with 4148 and solve for s:

4148 = 1.85s + 4.2(190)

Simplify:

4148 = 1.85 + 798

Subtract 798 from both sides:

3350 = 1.85s

Divide both sides by 1.85:

s = 1,810.81

Rounded to nearest square foot = 1811 square feet.

8 0

4 years ago

Read 2 more answers

Dentify as an increase or decrease. Then find the percent of increase or decrease. If necessary, round to the nearest percent.

love history [14]

Answer:

Step-by-step explanation:

The difference is 130-150 = -20, a decrease.

-20/150 ≅ -0.133, a decrease of 13.3%

4 0

3 years ago