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Sedaia [141]
3 years ago
14

Ramona went to the store with $18.55. After purchasing an item, she has $7.24 left. What was the cost of the

Mathematics
2 answers:
SOVA2 [1]3 years ago
7 0

Answer:

11.31

Step-by-step explanation:

if you subtract 7.24 from 18.55 you will have the answer 11.31

xeze [42]3 years ago
7 0

Answer:

The price of the item was $11.31.

Step-by-step explanation:

You simply subtract the two numbers that are given.

$18.55-$7.24 = $11.31.

And to even check your work, you could add the remaining money, to the solution you got from above.

11.31 + 7.24 gets you your starting amount $18.55.

Hope this helped you! :)

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tiff basic insurance cost is $613.50 per year. His insurance company offers a typical "safe-driver discount." What would be his
forsale [732]

The rate if he went three years without an accident based on the information about the insurance is $552.15.

<h3>How to calculate the insurance?</h3>

From the information given, his basic insurance cost is $613.50 per year and his insurance company offers a typical "safe-driver discount.

The amount will be:

= 613.50 - (20.45 × 3)

= 552.15

In conclusion, the rate is $552.15.

Learn more about insurance on:

brainly.com/question/25855858

#SPJ1

5 0
2 years ago
Pls show work! questions on pic
Lena [83]

Answer:

a.(10,23)

b.(7,30)

e.(20,20)

Step-by-step explanation:

We are given that

x=Width of garden

y=Length of garden

According to question

x\geq 5

y\geq 20

Perimeter of rectangle=2(x+y)

Where x=Width  of rectangle

y=Length of rectangle

Fencing used =2(x+y)

2(x+y)\leq 80

First we change inequality  into equality

x=5...(1)

y=20...(2)

2(x+y)=80

x+y=40...(3)

Substitute x=0 in equation (3)

y=40

Substitute y=0  in equation (3)

x=40

Substitute x=0 and y=0 in equation (3)

2(x+y)\leq 80

0\leq 80

It is true. Therefore, the  shaded region below the line.

0\geq 5

0\geq 20

These are false equation .Therefore, the shaded region above the line.

Substitute x=5 in equation (3)

5+y=40

y=40-5=35

Substitute y=20 in equation (3)

x+20=40

x=40-20=20

Intersection point of equation (1) and (3) is (5,35) and intersect point of equation (2) and (3) is (20,20).

Now,

a.(10,23)

Substitute in

2(x+y)\leq 80

2(10+23)\leq 80

66\geq 80

10>5 and 23>20

it satisfied all inequality.

Hence, it is a solution.

b.(7,30)

7>5

30>20

2(7+30)=74

it satisfied all inequality.

Hence, it is a solution.

c.(18,25)

18>5

25>20

2(18+25)=86>80

It does not satisfied third inequality

Hence, it is not a solution.

d.(8,35)

8>5

35>20

2(8+35)=86>80

It does not satisfied third inequality

Hence, it is not a solution.

e.(20,20)

2(20+20)=80

20>5

20=20

it satisfied all inequality.

Hence, it is a solution.

4 0
3 years ago
Hello, help me please)
AlladinOne [14]

Answer:

Given equation:

10^{5x-2}=2^{8x-3}

Take natural logs of both sides:

\implies \ln 10^{5x-2}= \ln 2^{8x-3}

\textsf{Apply log Power law}: \quad \ln_ax^n=n\ln_ax

\implies (5x-2)\ln 10=(8x-3) \ln 2

Expand brackets:

\implies 5x\ln 10 - 2\ln 10=8x \ln 2 -3 \ln 2

Collect like terms:

\implies 5x\ln 10 - 8x \ln 2 =2\ln 10-3 \ln 2

Factor left sides:

\implies x(5\ln 10 - 8 \ln 2) =2\ln 10-3 \ln 2

\textsf{Apply log Power law}: \quad \ln_ax^n=n\ln_ax

\implies x(\ln 10^5 - \ln 2^8) =\ln 10^2- \ln 2^3

\textsf{Apply log Quotient law}: \quad \ln_a\frac{x}{y}=\ln_ax - \ln_ay

\implies x\left(\ln\left(\dfrac{10^5}{2^8}\right)\right) =\ln\left(\dfrac{10^2}{2^3}\right)

Simplify:

\implies x\left(\ln\left(\dfrac{3125}{8}\right)\right) =\ln\left(\dfrac{25}{2}\right)

\implies x=\dfrac{\ln\left(\dfrac{25}{2}\right)}{\ln\left(\dfrac{3125}{8}\right)}

\implies x=0.4232297737...

6 0
2 years ago
$907,701,000,000 in scientific notation?<br><br><br> Please explain your answer! :)
Mumz [18]
907,701,000,000 in scientific notation is 9.07701 * 10^11.
8 0
3 years ago
What is 4x5 if 5xa=20
erastovalidia [21]

a=20÷5

a=4

5×4= 20

4×5= 20

3 0
3 years ago
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