The pasture is in the shape of a rectangle only the widths are marked.
a. Let x be the width of the pasture as labeled. Write an expression for the length in terms of x.
b. Write an expression for the area of the pasture in terms of x.
(a) the hedge along the length . we need to consider the three sides for fencing.
To find the length we use the given information
Dennis plans to use 1150 ft of fence to enclose a rectangular pasture.
Perimeter of rectangle = 2L + 2W
the hedge along the length, so we perimeter becomes L + 2W
Perimeter = L +2W, Width is x and perimeter is 1150
1150 = L + 2x ( subtract 2x on both sides)
So length L = 1150 - 2x
(b)Area of rectangle = length * width
We got L = 1150 -2x and we know width is x
Area = (1150-2x)*x
square feet
Answer:
line BC, 4 units right, and down 1 unit!
Hope This Helps!
Answer:
So then we expect the 99.7% of the finishing times would be between 68.5 s and 83.5 s for the 400 meters race
Step-by-step explanation:
Let X the random variable who represent the finishing times.
From the problem we have the mean and the standard deviation for the random variable X.
So then the parameters are
On this case in order to check if the random variable X follows a normal distribution we can use the empirical rule that states the following:
The probability of obtain values within one deviation from the mean is 0.68
, within two deviations we have 0.95 and within 3 deviations from the mean is 0.997
And from this rule we have 99.7 % of the values within 3 deviations from the mean, so we can find the limits like this:
So then we expect the 99.7% of the finishing times would be between 68.5 s and 83.5 s for the 400 meters race
C. Hope this helps. Good luck
Answer:
blue
Step-by-step explanation:
1/3·π·8∧2·8=536.17
(1/3·π·r∧2·h)