En un día laboral determinado, Saranne archiva el 50% de la

Plz ANWSER and make sure it’s in decimal form, plz show ur work <br> Overdue will mark brainest!

kari74 [83]

Answer:

Step-by-step explanation:The model will be of length 0.4 ft and the width being 0.28 feet

Step-by-step explanation:

Step 1.We know that the length of the building is 200 feet, and that the width of the building is 140 feet.

Step 2. the question tells us that "a 1/500 model is built of the building", meaning the problem wants to create a model using the ratio 1 feet for each 500 feet.

Step 3.So now to find the length and width of the model, we need to divide the given sides by 500.

Step 4. Side length of the Model = 200/500 = 2/5 = 0.4 feet

Step 5. Side width of the Model = 140/500 = 14/50 = 0.28 feet

There for giving us our final answer... "The model will be of length 0.4 feet and width 0.28 feet."

Hope I could help! :)

6 0

3 years ago

Read 2 more answers

Math

Snezhnost [94]

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

Here's the solution ~

$\qquad \sf \dashrightarrow \: 7.2 + (2x + 0.4)$

$\qquad \sf \dashrightarrow \: 7.2 + 2x + 0.4$

$\qquad \sf \dashrightarrow \: 7.2 +0.4 + 2x$

$\qquad \sf \dashrightarrow \: (7.2 +0.4) + 2x$

Therefore, the correct choice is A

3 0

2 years ago

Read 2 more answers

Suppose I am playing a sport that does not allow me to end a match in a tie (AKA I have to either win or lose). If my probabil

Leviafan [203]

Answer: The required probability is 0.3456.

Step-by-step explanation:

Since we have given that

Probability of winning at any given time = 0.6

Probability of losing at any given time = 1-0.6 = 0.4

Number of total matches = 5

Number of won matches = 3

So, using "Binomial distribution", we get that

$P(X=3)=^5C_3(0.6)^3(0.4)^2\\\\P(X=3)=0.3456$

Hence, the required probability is 0.3456.

6 0

3 years ago

1. The coordinates of the vertices of parallelogram RMBS are R(–4, 5), M(1, 4), B(2, –1), and S(–3, 0). Using the diagonals, pro

Whitepunk [10]

First, plot the points. Point R would be somewhere in the second Quadrant, point M would be in the first quadrant 1, point B would be in the fourth quadrant, and point S would be on the negative y-axis. A property of rhombi is that their diagonals are perpendicular. One would need to calculate the slopes of the diagonals and determine whether or not they are perpendicular. Lines are perpendicular if and only if their slopes are opposite reciprocals. Example: 2 and -0.5
Formulas needed:
Slope formula:
$\frac{ y_{2}- y_{1} }{ x_{2} - x_{1} }$

The figure would look kinda like this:
R
M

S
B
Diagonals are segment RB and segment SM
So, your slope equations would look like this:
$\frac{-1-5}{2-(-4)}$
and
$\frac{4-(-3)}{1-0}$
Slope of RB= -1
Slope of SM=7
Not a rhombus, slopes aren't perpendicular. But this figure may very well be a parallelogram

7 0

3 years ago

Consider the quadratic equation ax^2+bx+5=0,where a, b and c are rational numbers and the quadratic has two distinct zeros.

FrozenT [24]

You have shared the situation (problem), except for the directions: What are you supposed to do here? I can only make a educated guesses. See below:

Note that if   <span>ax^2+bx+5=0 then it appears that c = 5 (a rational number).

Note that for simplicity's sake, we need to assume that the "two distinct zeros" are real numbers, not imaginary or complex numbers. If this is the case, then the discriminant, b^2 - 4(a)(c), must be positive. Since c = 5,

b^2 - 4(a)(5) > 0, or b^2 - 20a > 0.

Note that if the quadratic has two distinct zeros, which we'll call "d" and "e," then

(x-d) and (x-e) are factors of ax^2 + bx + 5 = 0, and that because of this fact,

- b plus sqrt( b^2 - 20a )
d =  ------------------------------------
2a

and

</span> - b minus sqrt( b^2 - 20a )
e =  ------------------------------------
2a

Some (or perhaps all) of these facts may help us find the values of "a" and "b." Before going into that, however, I'm asking you to share the rest of the problem statement. What, specificallyi, were you asked to do here?

7 0

3 years ago