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BARSIC [14]
3 years ago
10

The value of 51/25 is​

Mathematics
1 answer:
Reika [66]3 years ago
6 0

Answer:

2 1/25

Step-by-step explanation:

51/25=2.04

2.04=2 1/25

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Ronald is distributing writing supplies to campers. He must give the same number of supplies to each camper and use all the supp
Liula [17]

Answer:

Robert can give writing supplies to at most 7 campers.

Step-by-step explanation:

The problem states that Robert must give the same number of supplies to each camper and use all the supplies. It means that the greatest number of campers that Robert can give writing supplies is the greatest common divisor(gcd) between the number of pencils and the number of note pads.

The gcd between two integers is the largest positive number that divides each of the integers. We can find this value by prime factorization.

The problem states that he has 14 pencils and 21 note pads. So we have to find gcd(14,21).

21 is not divisible by 2, so we try factoring by 3

14 is not divisible by 3, so we try factoring by 5

None of them are divisible by 5, so we move to 7

Both are divisible by 7, so

14 - 21 | 7

2  - 3

2<7, 3<7, so gcd(14,21) = 7.

Robert can give writing supplies to at most 7 campers.

3 0
4 years ago
A computer assembling company receives 24% of parts from supplier X, 36% of partsfrom supplier Y, and the remaining 40% of parts
Ivan

Answer:

thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)

Step-by-step explanation:

denoting A= a piece is defective , Bi = a piece is defective from the i-th supplier and Ci= choosing a piece from the the i-th supplier

then

P(A)= ∑ P(Bi)*P(C) with i from 1 to 3

P(A)= ∑ 5/100 * 24/100 + 10/100 * 36/100 + 6/100 * 40/100 = 9/125

from the theorem of Bayes

P(Cz/A)= P(Cz∩A)/P(A)

where

P(Cz/A) = probability of choosing a piece from Z , given that a defective part was obtained

P(Cz∩A)= probability of choosing a piece from Z that is defective = P(Bz) = 6/100

therefore

P(Cz/A)= P(Cz∩A)/P(A) = P(Bz)/P(A)= 6/100/(9/125) = 5/6 (83.33%)

thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)

8 0
3 years ago
Read 2 more answers
6√-20<br> Simplify the equation in simplest radical form <br> ≅
BigorU [14]

Answer:

12i sqrt5

Step-by-step explanation:

that is your answer so brainliest please

3 0
3 years ago
Suppose that Professor Rodgers needs one small group of students from his class to participate in a focus group. There are 11 st
irinina [24]

Answer:

(A) 165

(B) 330

Step-by-step explanation:

Total number of students in the class = 11

(A) How many different combinations of 3 selected students can he create?

ⁿCₓ = n! ÷ [(n - x)! x!]

n = 11,  x = 3

11! / [8! 3!]  = 165

<em>HINT:  8! or 8 factorial represents [8x7x6x5x4x3x2x1]</em>

(B) How many different combinations of 4 selected students can he create?

ⁿCₓ = n! ÷ [(n - x)! x!]

n = 11,  x = 4

11! / [7! 4!]  = 330

<em>Same hint applies here, for all numbers with the factorial sign.</em>

4 0
3 years ago
3²+3[2³(√49 - 2²)(3² - 2³)-2²}
lukranit [14]
3^2+3[2^3( \sqrt{49}-2^2)(3^2-2^3)-2^2]

Right off the bat, this may look crazy, but if we take it step by step, it will be much easier. So, let's take it step by step. If any step doesn't make sense to you, you can always hmu.

9+3[8( 7-4)(9-8)-4]
9+3[8( 3)(1)-4] = 9+3[24-4] = 9+3[20]
9+60 = 69

Your answer is 69. 
6 0
4 years ago
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