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3 years ago

I NEED HELP!!!!! PLEASE

Mathematics

1 answer:

lys-0071 [83]3 years ago

7 0

Answer:

I don't know

Step-by-step explanation:

your image is blocked on my computer. sorry

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Vlad [161]

Answer:

Fix the layout of the question because I cant tell the numbers

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Please help with 2 and 3 for maths

Vera_Pavlovna [14]

Answer:2-4=

Step-by-step explanation:y-16-(-42)

y-16+16

y-32

y-16-(-22)

y-16+4

y-20

y-16-(02)

y-16

y-16-(42)

y-0

8 0

3 years ago

Read 2 more answers

I need the answer for this exact question

denis23 [38]

Answer:

$y=\frac{7}{2}x-20$

Step-by-step explanation:

Let the equation of the line be $y-y_1=m(x-x_1)$ where, 'm' is its slope and $(x_1,y_1)$ is a point on it.

Given:

The equation of a known line is:

$y=-\frac{2}{7}x+9$

A point on the unknown line is:

$(x_1,y_1)=(4,-6)$

Both the lines are perpendicular to each other.

Now, the slope of the known line is given by the coefficient of 'x'. Therefore, the slope of the known line is $m_1=-\frac{2}{7}$

When two lines are perpendicular, the product of their slopes is equal to -1.

Therefore,

$m\cdot m_1=-1\\m=-\frac{1}{m_1}\\m=-\frac{1}{\frac{-2}{7} }=\frac{7}{2}$

Therefore, the equation of the unknown line is determined by plugging in all the given values. This gives,

$y-(-6))=\frac{7}{2}(x-4)\\y+6=\frac{7}{2}x-14\\y=\frac{7}{2}x-14-6\\\\y=\frac{7}{2}x-20$

The equation of a line perpendicular to the given line and passing through (4, -6) is $y=\frac{7}{2}x-20$ .

3 0

3 years ago

How do you factor out the coefficient of 2.2x+4.4

NISA [10]

2.2x and 4.4 have a GCF of 2.2. So, you can factor that out like so:
2.2x+4.4 = 2.2*x+2.2*2 = 2.2(x+2)

Hope this helps!

8 0

3 years ago

Rearrange the equation so a is the independent variable.<br><br> 3a-7= -4b+1<br><br> Please help! :)

Aleksandr-060686 [28]

Answer:

Hiii the answer would be a= -4b+8/3

7 0

3 years ago

I NEED HELP!!!!! PLEASE ​

I NEED HELP!!!!! PLEASE