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Leya [2.2K]
3 years ago
10

HELP Please! Can someone solve any of these problems?

Mathematics
1 answer:
enyata [817]3 years ago
3 0

Answer:

i love brent faiyaz

Step-by-step explanation:

there you are

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Identify the action-reaction pair when a softball player hits a home run
Mariulka [41]

Answer:

Newton's third law of motion states that every action has an equal and opposite reaction. In softball when the catcher catches the ball the two forces present are the mitt on the ball and the ball on the mitt. The two are equal and in opposite directions.

4 0
3 years ago
What is the volume of a frustum of a rectangular pyramid if one base has measurements 6 ft. × 8 ft., the other base has measurem
RoseWind [281]
To solve this, we use the formula for the volume of the frustum of a cone which is expressed as:

<span>V= (H/6)[WL + (W+a)(L+b) + ab]
</span>V = 3/6 [(6 ft. × 8 ft.) + (6 + 14)(18 + 8) + (<span>14 ft. × 18 ft.)]
</span>V = 409.98 ft^3 <-----OPTION C 
7 0
3 years ago
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Question 1
AnnyKZ [126]

Answer:

1. x=17

2. x=19

3. x=3

4. x=4

3 0
2 years ago
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Last week, the price of oranges at the farmers market was $1.75 per pound. This week, the price has decreased by 15%. What is th
aliina [53]

Answer:

 11.6 (6 is repeating)

Step-by-step explanation:

1.75 divided by 15% of 75

3 0
2 years ago
Consider the differential equation
Gennadij [26K]

The first solution is quadratic, so its derivative y' on the left side is linear. But the right side would be a polynomial of degree greater than 1, so this is not the correct choice.

The third solution has a similar issue. The derivative of √(x² + 1) will be another expression involving √(x² + 1) on the left side, yet on the right we have y² = x² + 1, so that the entire right side is a polynomial. But polynomials are free of rational powers, so this solution can't work.

This leaves us with the second choice. Recall that

1 + tan²(x) = sec²(x)

and the derivative of tangent,

(tan(x))' = sec²(x)

Also notice that the ODE contains 1 + y². Now, if y = tan(x³/3 + 2), then

y' = sec²(x³/3 + 2) • x²

and substituting y and y' into the ODE gives

sec²(x³/3 + 2) • x² = x² (1 + tan²(x³/3 + 2))

x² sec²(x³/3 + 2) = x² sec²(x³/3 + 2)

which is an identity.

So the solution is y = tan(x³/3 + 2).

4 0
2 years ago
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