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vovikov84 [41]
3 years ago
11

Alicia can type 198 words in 3 minutes. How many words can she type in 1 minute?

Mathematics
2 answers:
arsen [322]3 years ago
8 0
66 words In a minute
ycow [4]3 years ago
5 0
She can type 66 words in 1 minute
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A scientist claims that 6% of viruses are airborne. (a) If the scientist is accurate, what is the probability that the proportio
soldi70 [24.7K]

Answer:

Probability that the proportion of airborne viruses in a sample of 529 viruses would be greater than 8% is 0.9545.

Step-by-step explanation:

For the given population the distribution of air-borne viruses is given as 6%. Now for this the value of Z score is given as

Z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}}

Here

  • \hat{p} is the sample measure which is 8% or 0.08
  • p is the population measure which is 6% or 0.06
  • n is the number of samples which is 529

So the Z score is given as

Z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}}\\Z=\dfrac{0.08-0.06}{\sqrt{\dfrac{0.08(1-0.08)}{529}}}\\Z=\dfrac{0.02}{\sqrt{\dfrac{0.08(0.92)}{529}}}\\Z=\dfrac{0.02}{\sqrt{\dfrac{0.0736}{529}}}\\Z=\dfrac{0.02}{0.01179}\\Z=1.6955

For this the score, the value of probability is calculated from the table as below:

P(\hat{p}>0.08)=p(Z>1.6955)\\=1-p(Z

Here value of p(Z<-1.6955) is given as 0.0455

P(\hat{p}>0.08)=p(Z>1.6955)\\P(\hat{p}>0.08)=1-p(Z0.08)=1-0.0455\\P(\hat{p}>0.08)=0.9545

 

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What is the length of the dotted line in the diagram below? Leave your answer in
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The top is a triangle with sides 7 and 5.4 Use the Pythagorean theorem to find the 3rd length.

3rd sides = sqt(7^2 + 5^2( = sqrt(49+25) = sqrt(74)

This side is the base of the lower rectangle.

The dotted line is the hypotenuse of a right triangle.

Use the Pythagorean theorem to solve.

sqrt(10^2 + sqrt(74)^2) = sqrt(174)

The dotted line = sqrt(174)

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Answer:

the incorrect option is

D

because tan is opposite/adjacent

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Answer:

I uploaded a file hosting link for your question.

See below for more details.

Step-by-step explanation:

m=\frac{change(y)}{change(x)}

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