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2 years ago

Please help y≥1/3x-3

Mathematics

1 answer:

zloy xaker [14]2 years ago

6 0

Answer:

B, the one with the line and shaded the top on the right side. (The one that goes to 7 on the x axis).

Step-by-step explanation:

First I find which graph as y -intercept of -3, which is all of them.

Next, I find with graph has a slope of 1/3. (rise 1 run 3). Only B and D has a slope of 1/3 (The ones that has a less steep graph. )

Then, I use the coordinate (0,0) to see which side the graph shades. I plug it into the inequality. (0)≥1/3(0)-3. Solve. Is 0 greater than -3. YES! so we shade the part where (0,0) is shaded which is B.

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Step-by-step explanation:

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2 years ago

How can you use the point-slope form of a line when only given two points?

pshichka [43]

Answer:

See below

Step-by-step explanation:

Point -slope form is:

y - y1 = m(x - x1)

By having one set of coordinates and knowing the value of the slope (m in the equation) you can use the form.

How to find the slope?

Here you need 2 points: Point 1 with coordinates x1, y1 and point 2 with the coordinates x2, y2

Use the formula:

m = (y2-y1)/(x2-x1)

Example:

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3 years ago

What is the product?

AleksandrR [38]

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3 years ago

Help please rn help

aksik [14]

Area of the large semicircle

$= \pi{r}^{2} \div 2$

$= \frac{22}{7} \times 12 {}^{2} \times \frac{1}{2}$

$= \frac{11}{7} \times12 \times 12$

$= \frac{11}{7} \times 144$

$= 226.28$

Area of the small semicircle

$= \pi {r}^{2} \div 2$

$= \frac{22}{7} \times 6 {}^{2} \times \frac{1}{2}$

$= \frac{11}{7} \times 6 \times 6$

$= \frac{11}{7} \times 36$

$= 56.57$

Area of the figure

$= 226.28 - 56.57$

$= 169.71 {cm}^{2}$

8 0

3 years ago

Given the following coordinates complete the reflection transformation. A(1,−5) B(2,−2) C(5,−2) Transformation: Complete the dou

Dmitriy789 [7]

Answer:

A''(1,-1) B''(2,2) C''(5,2)

Step-by-step explanation:

Points A(1,−5) B(2,−2) C(5,−2)

reflection over y=-1

Perpendicular distance between points y-coordinates of points (A, B and C) and y=-1 are 4,1 and 1

after reflections, the perpendicular distance will be 8,2,2 and the points will be at

A'(1,3) B'(2,0) C'(5,0)

again reflection over y=1

Perpendicular distance between points y-coordinates of points (A', B' and C') and y=1 are 2,1 and 1

after reflections, the perpendicular distance will be 4,2,2 and the points will be at

A''(1,-1) B''(2,2) C''(5,2)!

7 0

3 years ago

Please help y≥1/3x-3​

Please help y≥1/3x-3