Answer:
Explanation:
Its a R-type instruction:
31 25 24 20 19 15 14 12 11 7 6 0
+------------+---------+---------+------+---------+-------------+
| funct7 | rs2 | rs1 |funct3| rd | opcode |
+------------+---------+---------+------+---------+-------------+
Assembly Language Instruction:
sub rd, rs1, rs2 || 0x0 0x20 || R[rd] ← R[rs1] - R[rs2]
Binary Conversion:
R-TYPE funct7 rs2 rs1 funct3 rd opcode
Bits 7 5 5 3 5 7
Binary 100000 00101 00111 000 00110 0110011
So Binary representation for this is: 0100 0000 0101 0011 1000 0011 0011 0011
Solution :
Here, we need to perform JOIN operation of the students and registration.
Use NATURAL JOIN operator 
and so no need to specify Join condition.
Also we need to selection operator tp select only those course whose major in "philosophy".
Finally we projection operator π to project only distinct students name who took at least three courses.
![$\pi [\sigma_{\text{student's nam}e} [ \sigma(\text{three courses}) \Join \text{"Philosophy"}]]$](https://tex.z-dn.net/?f=%24%5Cpi%20%5B%5Csigma_%7B%5Ctext%7Bstudent%27s%20nam%7De%7D%20%5B%20%5Csigma%28%5Ctext%7Bthree%20courses%7D%29%20%5CJoin%20%5Ctext%7B%22Philosophy%22%7D%5D%5D%24)
Answer:
Explanation:
String str = "Broccoli is delicious.";
String[] Secondstr = str.split(" ");
System.out.println("second word is " + Secondstr[1]);
Answer:
Click the “Insert” tab, then click the “Chart” button on the Illustrations section to open the “Insert Chart” pop-up window.
Select the type of graph to add to the document, such as a pie chart or bar graph. ...
Click “OK” and Word adds a chart with generic data points to the document.
Explanation:
E-text <span>is digital textual information that can be stored, manipulated, and transmitted by electronic devices. The term "e-text" stands for electronic text and it is used for any digital document written, read, transmitted or manipulated by electronic devices, such as smart phones, PCs, tablets,...The origins of the e-text are in the beginning of the Internet.</span>
