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3 years ago

What sugar is used in a DNA molecule

Computers and Technology

2 answers:

Sliva [168]3 years ago

5 0

Answer:

Ribose and Deoxyribose. The 5-carbon sugars ribose and deoxyribose are important components of nucleotides, and are found in RNA and DNA, respectively. The sugars found in nucleic acids are pentose sugars; a pentose sugar has five carbon atoms. A combination of a base and a sugar is called a nucleoside.

Explanation:

mario62 [17]3 years ago

3 0

Answer:

Deoxyribose and ribose

Explanation:

The backbone of DNA is based on a repeated pattern of a sugar group and a phosphate group. The full name of DNA, deoxyribonucleic acid, gives you the name of the sugar present - deoxyribose. Deoxyribose is a modified form of another sugar called ribose.

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alexdok [17]

Answer:

The answer is "102.2 milliseconds".

Explanation:

Given:

Size of file = 15 MiB

The transmission rate of the total link= 49.7 Gbps

User = 7

Time of setup = 84.5 ms

calculation:

$1\ MiB = 2^{20} = 1048576\ bytes\\\\1\ MiB = 2^{20 \times 8}= 8388608\ bits\\\\15\ MiB= 8388608 \times 15 = 125829120\ bits\\\\$

So,

Total Number of bits $= 125829120 \ bits$

Now

The transmission rate of the total link= 49.7 Gbps

$1\ Gbps = 1000000000\ bps\\\\49.7 \ Gbps = 49.7 \times 1000000000 =49700000000\ bps\\\\FDM \ \ network$

$\text{Calculating the transmission rate for 1 time slot:}$

$=\frac{ 49700000000}{7} \ bits / second\\\\= 7100000000 \ bits / second\\\\ = \frac{49700000000}{(10^{3\times 7})} \ in\ milliseconds\\\\ =7100000 \ bits / millisecond$

Now,

$\text{Total time taken to transmit 15 MiB of file} = \frac{\text{Total number of bits}}{\text{Transmission rate}}$

$= \frac{125829120}{7100000}\\\\= 17.72\\\\$

$\text{Total time = Setup time + Transmission Time}\\\\$

$= 84.5+ 17.72\\\\= 102.2 \ milliseconds$

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3 years ago

User Jsmith is a member of the Accounting and Contractor groups, and is trying to save a file to Folder A on his local computer,

DochEvi [55]

Answer and Explanation:

Jsmith's membership in the Contractor group means that he has been denied all access to the folder.

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umka21 [38]

Answer:

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Explanation:

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3 years ago

The FAT method ______________.

AnnyKZ [126]

The FAT method incorporates free-block accounting into the allocation data structure.

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2 years ago

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Viktor [21]

Answer:

The program only runs 5 five since the for loop statement is limited to loop only five times.

Explanation:

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3 years ago

What sugar is used in a DNA molecule​

What sugar is used in a DNA molecule