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Scrat [10]
3 years ago
10

What is the slope of the line that passes through the given points? (6, 2) and (7, 4)

Mathematics
2 answers:
zhannawk [14.2K]3 years ago
7 0

Slope for (x₁, y₁) and (x₂, y₂):      (6, 2) and (7, 4)

Slope:      (y₂ -y₁) / (x₂ -x₁)

Slope:      ( 4 - 2) / (7 - 6)  =  2/1

<span>Slope = 2/1 = 2

Option D</span>
djyliett [7]3 years ago
6 0

Hello!

Step-by-step explanation:

Slope: \frac{Y^2-Y^1}{X^2-X^1}=\frac{rise}{run}

\frac{4-2=2}{7-6=1}=\frac{2}{1}=2

<em><u>Slope is 2.</u></em>

<em><u>Answer 2. </u></em>

Hope this helps!

Thanks!

-Charlie

Have a great day!

:)

:D

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Write the equation of a line passing through (6,-2) and perpendicular to -2x + 3y= -6
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Perpendicular lines refers to a pair of straight lines that intercept each other. The slopes of this lines are opposite reciprocal, meaning that it's multiplication is -1.
On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.


-2x+3y=-6                 Add 2x in both sides
3y=2x-6                    Divide by 3 in both sides to isolate y
y=2/3x-6/3


The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.

y=mx+b                 Substitute the given point and the previous slope found
-2=(-3/2)(6)+b       Combine like terms
-2=-9+b                 Add 9 in both sides to isolate b
7=b

The equation that represents the line perpendicular to -2x+3y=-6 and that passes through the point (6,-2), is y=-3/2x+7.


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