6⋅10 −2 6, dot, 10, start superscript, minus, 2, end superscript is how many times as large as 2 ⋅ 1 0 − 8 2⋅10 −8 2, dot, 10, s
tart superscript, minus, 8, end superscript?
1 answer:
Answer:
<em>6⋅10^ −2 is 3* 10^6 greater than 2 ⋅ 10^− 8</em>
Step-by-step explanation:
Given the following expression
6⋅10^ −2 and 2 ⋅ 10^− 8
Taking their ratio
k = 6⋅10^ −2/2 ⋅ 10^− 8
k = 6/2 * 10^-2/10^-8
k = 3 * 10^{-2+8}
k = 3* 10^6
<em>Hence 6⋅10^ −2 is 3* 10^6 greater than 2 ⋅ 10^− 8</em>
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