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Mekhanik [1.2K]
3 years ago
10

the distance that a spring will stretch varies directly as the force applied to the spring. A force of 12 pounds is needed to st

retch a spring 9 inches. What force is required to stretch the spring 15 inches?
Mathematics
2 answers:
Luda [366]3 years ago
5 0

Answer:Force required, F = 20 pounds

Step-by-step explanation:

We have given,

force needed to stretch a spring , F = 12 pounds

Stretched length, x = 9 inches

Since, spring force formula can be given as: F = kx

i.e 12 = k · 9

or k =  = 4/3

Now we need to find force for the stretch length = 15 inches

i.e F = kx   , here x =15inches , k = 4/3 and F= ?

or F = (4/3) · 15

or F = 20 pounds

Hence force required, F= 20 pounds

Read more on Brainly.com - brainly.com/question/12027158#readmore

Step-by-step explanation:

vodka [1.7K]3 years ago
4 0

Answer:

Force required, F = 20 pounds

Step-by-step explanation:

We have given,

force needed to stretch a spring , F = 12 pounds

Stretched length, x = 9 inches

Since, spring force formula can be given as: F = kx

i.e 12 = k · 9

or k = \frac{12}{9} = 4/3

Now we need to find force for the stretch length = 15 inches

i.e F = kx   , here x =15inches , k = 4/3 and F= ?

or F = (4/3) · 15

or F = 20 pounds

Hence force required, F= 20 pounds

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            11

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<h3>Divide. </h3>

x¯= 23.75 18

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

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<h3>Simplify each value in the list. </h3>

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Set up the formula for sample standard deviation. The standard deviation of a set of values is a measure of the spread of its values.

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                            N-1

             

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<h3>Simplify the result. </h3>

 

s= √68.05209

The standard deviation should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

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Step-by-step explanation:

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