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Ronch [10]
3 years ago
15

The probability that Rahul succeeds at any given free-throw is 70%, percent. He was curious how many free-throws he can expect t

o succeed in a sample of 15 free-throws.
He simulated 30 samples of 15 free-throws where each free-throw had a 0.7, probability of being successful.

Rahul counted how many free-throws were successful in each simulated sample. Here are his results:

(picture attached)

Use his results to estimate the probability that he succeeds at 11 or fewer free-throws in a sample of 15 free-throws. Give your answer as either a fraction or a decimal.

P(11 or fewer sucessess) =

Mathematics
1 answer:
True [87]3 years ago
8 0

Answer:

Step-by-step explanation:is 13/20=0.65

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Answer:

y =  x - 2

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Factor completely: 4a^2+b^2−c^2+4ab
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Answer:

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Step-by-step explanation:

Here, the given expression is 4a^{2} + b^{2}  - c^{2}  + 4ab

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Now, by ALGEBRAIC IDENTITY: (x+y)^{2}  = x^{2} + y^{2}  + 2xy

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Hence, on simplification, the expression

(4a^{2} + b^{2}  + 4ab ) - c^{2} = (2a + b)^{2} - c^{2}

Now, by ALGEBRAIC IDENTITY: (x +y)(x-y) = x^{2}  - y^{2}

So, similarly  (2a + b)^{2} - c^{2}= (2a + b -c) (2a + b+c)

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