I believe the answer is 17
Answer:
40 mph
Step-by-step explanation:
We assume "outbound" refers to the trip <em>to the lake</em>. The ratio of speeds is inversely proportional to the ratio of times, so ...
outbound speed : inbound speed = 4 : 3
These differ by one ratio unit, so that one ratio unit corresponds to the speed difference of 10 mph. Then the 4 ratio units of outbound speed will correspond to ...
4×10 mph = 40 mph
Paul's average speed on the outbound trip was 40 mph.
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The distance to the lake was 120 mi.
Answer: The height of the tree is 27f
t
Step-by-step explanation: We can set up a proportion comparing the height of each object to the length of the shadow.
h/s
h/15=18/10
Cross multiply
10.h= 18*15
10h=270
Use the multiplicative Inverse
10
h/
10
=
<em><u>270
/10
=27</u></em>
Multiply base time height. Simply put B(H)=A
B=3 1/2
H=2 2/3
A=(3 1/2)(2 2/3)
A=28/3
A=9.3333
C)
It’s far off from most of the points
