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Lerok [7]
3 years ago
13

Please help i will mark branliest

Mathematics
1 answer:
konstantin123 [22]3 years ago
7 0

Answer:

1

Step-by-step explanation:

The range is the difference between the largest and smallest values.

range = 9 - 2 = 7

If 2 is replaced by 3 then 3 becomes the smallest value and

range = 9 - 3 = 6

That is the range decreases by 1

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Help quickly please!!!
vagabundo [1.1K]

Answer:

1/3 B h

1/3(50.24)(10)

plug in into a calculator

6 0
3 years ago
A store is having a 20% off sale. If the reduced
FinnZ [79.3K]

Answer:

The original price of the item was $83

Step-by-step explanation:

5 0
3 years ago
If a 5-pound bag of potatoes costs $5.25 , then how much would 7 pounds cost?
sashaice [31]

Answer:

7.35

Step-by-step explanation:

5 pounds -> 5.25

1 pound -> 1.05

7 pounds-> 7.35

4 0
3 years ago
Gianna has a two $3,000 one year CDs at different banks. Each compounds
sertanlavr [38]

Answer:

Option D

Step-by-step explanation:

To calculate compound interest we will use the formula :

A=P(1+\frac{r}{n})^{nt}

Where,

A = Amount on maturity

P = Principal amount = $3000

r = rate of interest = 8.4% = 0.084

n = number of compounding period = Monthly = 12

t = time = 1 year

Now put the values in the formula.

A=3000(1+\frac{0.08}{12})^{(12)(1)}

   = 3000(1+0.007)^{12}

   = 3000(1.007)¹²

   = 3000 × 1.08731066

   = 3261.93198 ≈ $3261.93

While the other bank compounds interest daily.

Therefore, n = 365

Now put the values in the formula with n = 365

=3000(1+\frac{0.084}{365})^{(365)(1)}

=3000(1+0.00023014)^{365}

=3000(1.00023014)^{365}

= 3000 × 1.08761958

= 3262.85874 ≈ $3262.86

Difference in the ending balance = 3262.86 - 3261.93

                                                       = $0.93

The difference in the ending balances of both CDs after one year would be $0.93.

8 0
3 years ago
find the solution to the system. write your solution as an ordered pair (x,y) with no spaces, no solution or infinitely many 2x-
Kitty [74]

Answer:

(-8,4)

Step-by-step explanation:

Given: 2x-3y=-28 and x+6y=16

solve for a variable and then substitute back into other equation

x + 6y = 16

x = 16 - 6y; now use this in the other equation

2x - 3y = -28; substitute into x

2(16 - 6y) - 3y = -28; distribute 2

32 - 12y - 3y = -28; combine y's

32 - 15y = -28; isolate 15y

32 + 28 = 15y; add the numbers

60 = 15y; divide by 15

y = 4

Now use this to plug into other equation

x + 6y = 16; y=4

x + 6(4) = 16;

x + 24 = 16; subtract 24 from both sides

x = -8

4 0
3 years ago
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