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3 years ago

15

Marc decides put molding around his bathroom floor. The room is 6’ x 8’. How much molding will he need? Answer: _ feet (type the

number only)

2 answers:

viktelen [127]3 years ago

6 0

48
explanation : 6 x 8 = 48

Inessa [10]3 years ago

4 0

A=l•w
A=6•8
A=48 ft sq

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Can someone please explain to me how to do this.

JulijaS [17]

Y = x² - 4x + 4
y = 2x - 4

Find intersection of L and C:
x² - 4x + 4 = 2x - 4
x² - 6x + 8 = 0
<span> (x - 2)(x - 4) = 0
x = 2 or x = 4

When x = 2 , y = 2(2) - 4 = 0
When x = 4, y = 2(4) - 4 = 4

Points of intersection = A(2, 0) and B(4, 4)

Find the length of AB:

</span> $
\text {Length of AB}= \sqrt{(4-0)^2 + (4-2)^2} = \sqrt{16 + 4} = \sqrt{20} = 4.47 \text{ units}$
<span>
Answer: 4.47 units

</span>

4 0

3 years ago

Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt

polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

$\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt$

$=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k$

The first integral is trivial since $(\tan t)'=\sec^2t$ .

The second can be done by substituting $u=t^2-1$ :

$u=t^2-1\implies\mathrm du=2t\,\mathrm dt\implies\displaystyle\frac12\int u^8\,\mathrm du=\frac1{18}(t^2-1)^9+C$

The third can be found by integrating by parts:

$u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t$

$\mathrm dv=t^7\,\mathrm dt\implies v=\dfrac18t^8$

$\displaystyle\int t^7\ln t\,\mathrm dt=\frac18t^8\ln t-\frac18\int t^7\,\mathrm dt=\frac18t^8\ln t-\frac1{64}t^8+C$

8 0

3 years ago

Calculate the area of a rectangle if its dimensions are listed below:

Marizza181 [45]

Answer:

Length=10x

Breadth=7x

Area=10x×7x

=70x²

3 0

2 years ago

Read 2 more answers

9. To fill up his fuel tank, Sam puts in 16.8 gallons of gas at $3.90 per gallon. How much does Sam spend on fuel? Round to the

Verizon [17]

Answer:

$65.52

Step-by-step explanation:

y = mx + b

y = amount spent on fuel = ?

m = price per gallon = $3.90

x = gallons = 16.8

b is not needed for this problem

y = (3.90)(16.8)

y = $65.52

8 0

2 years ago

Consider the function and its inverse.

Ber [7]

Answer:

The domain of $f(x)$ is restricted to $x\leq 0$ , and the domain of $f^{-1}(x)$ is restricted to $x\geq 4$ .

Step-by-step explanation:

From Function Theory we know that domain of a function is the set of values such that an image exist. Let $f(x) = x^{2}+4$ and $f^{-1}(x) = \sqrt{x-4}$ the function and its inverse, respectively.

At first glance we notice that function is a second order polynomial and every polinomial is a continuous function and therefore, there exists an image for every element of domain.

But domain of its inverse is restricted to every value of x so that $x-4 \geq 0$ , which means that $x\geq 4$ .

Finally, we concluded that following answer offers the best approximation to our result:

The domain of $f(x)$ is restricted to $x\leq 0$ , and the domain of $f^{-1}(x)$ is restricted to $x\geq 4$ .

6 0

2 years ago