If 7 action figures are on each shelf
Then
in 2 shelves, there are
2x7 = 14 figures
Answer is
shelves hold 14 figures
Ok so for number one is 6in the radius? And for number two your answer is C. 250 in. Squared.
Answer:
a. Function 1
b. Function 3
c. Function 2, Function 3 and Function 4
Step-by-step explanation:
✔️Function 1:
y-intercept = -3 (the point where the line cuts across the y-axis)
Slope, using the two points (0, -3) and (1, 2):
Slope = 5
✔️Function 2:
y-intercept = -1 (the value of y when x = 0)
Slope, using the two points (0, -1) and (1, -4):
Slope = -3
✔️Function 3: y = 2x + 5
y-intercept (b) = 5
Slope (m) = 2
✔️Function 4:
y-intercept = 2
Slope = -1
Thus, the following conclusions can be made:
a. The function's graph that is steepest is the function whose absolute value of its slope is greater. Therefore Function 1 is the steepest with slope of 5
b. Function 3 has a y-intercept of 5, which is the farthest from 0.
c. Function 2, Function 3, and Function 4 all have y-intercept that is greater than -2.
-1, 5, and 2 are all greater than -2.
Answer:
Step-by-step explanation:
I'm guessing A and J. Makes the most sense.
Slope of line = tan(120) = -tan(60) = - √3
Distance from origin = 8
Let equation be Ax+By+C=0
then -A/B=-√3, or
B=A/√3.
Equation becomes
Ax+(A/√3)y+C=0
Knowing that line is 8 units from origin, apply distance formula
8=abs((Ax+(A/√3)y+C)/sqrt(A^2+(A/√3)^2))
Substitute coordinates of origin (x,y)=(0,0) =>
8=abs(C/sqrt(A^2+A^2/3))
Let A=1 (or any other arbitrary finite value)
solve for positive solution of C
8=C/√(4/3) => C=8*2/√3 = (16/3)√3
Therefore one solution is
x+(1/√3)+(16/3)√3=0
or equivalently
√3 x + y + 16 = 0
Check:
slope = -1/√3 .....ok
distance from origin
= (√3 * 0 + 0 + 16)/(sqrt(√3)^2+1^2)
=16/2
=8 ok.
Similarly C=-16 will satisfy the given conditions.
Answer The required equations are
√3 x + y = ± 16
in standard form.
You can conveniently convert to point-slope form if you wish.
