Hello!
First you have to get the equation into slope-intercept form
Slope-intercept form is y = mx + b
-2x + 4y = -8
Add 2x to both sides
4y = 2x - 8
Divide both sides by 4
y = 1/2 x - 2
The graph is a line that goes through the points (0, -2), (-2, -3), (2, -1) and
(4, 0)
Hope this helps!
Answer:
y = mx + 5; m < 0
Step-by-step explanation:
The question mentions that the slope of the line is negative and the y-intercept is 5. The general form of the straight line is given by y = mx + c. Since "c" in the equation is the y-intercept, therefore, c = 5. This means that all the straight lines passing from the point (0,5) can be expressed in a general form y = mx + 5. However, the question mentions that the slope is negative and demands the general equation of all the negatively-sloped straight lines passing from (0,5). Therefore, for the condition to be met, m has to be negative. So the correct answer is y = mx + 5, where m is negative.
Answer:
i dont see a circle
Step-by-step explanation:
I believe the answer is 4. I did an assignment and got it right