Answer:
222,222,222,222,222,222,222,222,222,222
Step-by-step explanation:
Intellegenc.
What can we help you with?
Let x and y be your two consecutive whole numbers
x < sqrt(142) < y
x^2 < 142 < y
So, we are looking for x and y such that x^2 < 142 and y^2 > 142.
The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.
11 and 12 are consecutive.
11^2 = 121 < 142 < 144 = 12^2
Thus, 11 and 12 are your numbers
Answer:
x = 32
Step-by-step explanation:
Using the Secant and Tangent Intersection Theorem we can say;
(x + 18) (18) = 30²
18x + 324 = 900
18x = 576
x = 32
Hope this helps!
