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____ [38]
2 years ago
5

Tickets to a carnival cost $28.75 each. What is y, the cost of x tickets?

Mathematics
1 answer:
trasher [3.6K]2 years ago
6 0

Answer:

y = $28.75x

Step-by-step explanation:

Given that,

Tickets to a carnival cost $28.75 each.

We need to find y i.e. the cost of x tickets.

When the number of tickets are x, to find the cost of x tickets, we must find it by multiplying 28.75 and x i.e.

y = 28.75x

Hence, the cost of x tickets is equal to $28.75x.

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Which function in vertex form is equivalent to f(x) = x2 + 6x + 3?
8_murik_8 [283]
Complete the square
move the 3 aside and work in parenthasees
f(x)=(x^2+6x)+3
take 1/2 of 6 and square it (6/2=3, 3^2=9)
add 9 and -9 inside
f(x)=(x^2+6x+9-9)+3
factor perfect square
f(x)=((x+3)^2-9)+3
get rid of parenthases
f(x)=(x+3)^2-9+3
f(x)=(x+3)^2-6

2nd choice
4 0
2 years ago
Read 2 more answers
Solve the following problems:
lorasvet [3.4K]

Answer:

The measure of side MO is 8 unit

Step-by-step explanation:

Given as :

In the Triangle ΔMOP ,

∠P = 90°

∠M = 60°

The perimeter of  ΔMOP = 12 + 4√3

Now, From figure , in Triangle ΔMOP

∠O = 180° - ( ∠P + ∠M )

or, ∠O = 180° - ( 90° + 60° )

or,  ∠O = 180° - 150°

∴ ∠O = 30°

<u>Now, from Triangle</u>

Sin 90° = \dfrac{\textrm perpendicular}{\textrm hypotenuse}

Or, Sin 90° = \dfrac{\textrm OP}{\textrm OM}

Or,  \dfrac{\textrm OP}{\textrm OM} = 1

Again

Sin 60° = \dfrac{\textrm perpendicular}{\textrm hypotenuse}

Or, Sin 60° = \dfrac{\textrm OP}{\textrm OM}

Or,  \dfrac{\textrm OP}{\textrm OM} = \dfrac{\sqrt{3} }{2}

Similarly

Sin 30° = \dfrac{\textrm base}{\textrm hypotenuse}

Or, Sin 30° = \dfrac{\textrm PM}{\textrm OM}

Or,  \dfrac{\textrm PM}{\textrm OM} = \frac{1}{2}

So, The ratio of the sides as

PM : MO : OP = 1 : 2 : \sqrt{3}

Let  PM = x

MO = 2 x

OP = x\sqrt{3}

Now, from question

The perimeter of triangle ΔMOP = 12 + 4√3

I.e, The sum of sides of triangle ΔMOP = 12 + 4√3

or, PM + MO + OP = 12 + 4√3

or, x + 2 x +  x\sqrt{3} = 12 + 4√3

or, 3 x  +  x\sqrt{3} = 12 + 4√3

Or, x ( 3 +\sqrt{3} ) = 4 ( 3 +\sqrt{3} )

Now, equating both side we get

x = 4

So, The measure of side MO = 2 x

I.e The measure of side MO = 2 × 4 = 8 unit

Hence The measure of side MO is 8 unit   Answer

5 0
3 years ago
BRIA is a rectangle. AN=5. NR=x-3. please solve for x, NR, and BI
Lena [83]

Answer:

x=8

NR=5 units

BI=10 units

Step-by-step explanation:

In  a rectangle BRIA

AN=5 units

NR=x-3

We have to solve for x , NR and BI.

We know that

Diagonals of rectangle bisect to each other.

BI and AR are the diagonals of rectangle BRIA and intersect at point N.

AN=NR

5=x-3

x=5+3=8

x=8

Substitute the value of x

NR=8-3=5

By property of rectangle

BI=AR=AN+NR=5+5=10 unit

BI=10 units

7 0
2 years ago
What is the first multiple of 30 that is divisible by 4?
kap26 [50]
Multiples of 30 : 30,60,90,120,150....

and the first one that 4 goes into evenly is 60
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3 years ago
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Mateo teaches a continuing education class at the library on tuesday nights. he estimates that 75% of his students are satisfied
vredina [299]

The computed value must closely match the real value for a model to be considered valid. If the percentage of pleased or very satisfied students remains close to 75% after Mateo surveys additional students, Mateo's model is still viable. The model is faulty if the opposite is true.

<h3>How will mateo know whether his model is valid or not?</h3>

In general, a valid model is one whose estimated value is close to the real value. This kind of model is considered to be accurate. It must be somewhat near to the real value if it doesn't resemble the real value.

If the findings of the survey are sufficiently similar to one another, then the model may be considered valid.

P1 equals 75%, which is the real assessment of the number of happy pupils

P2 is 70 percent; this represents the second assessment of happy pupils

In conclusion,  The estimated value of a model has to be somewhat close to the real value for the model to be considered valid. If the number of students who are either pleased or extremely satisfied remains close to 75 percent following Mateo's survey of more students, then Mateo's model is likely accurate. In any other scenario, the model cannot be trusted.

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7 0
1 year ago
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