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3 years ago

Could somebody please help me find the answers for 'x' for these pictures?

Mathematics

2 answers:

mario62 [17]3 years ago

5 0

These are the answers! I hope this helps!
1. x=51
2. x=5
3. x=12

djyliett [7]3 years ago

4 0

Answer:

(in order) #1

for the first one you have a vertical angle. Vertical angle is basically any 2 lines who intersect each other. The opposite sides will be congruent.

So in this case

2x+8 and 110 are oppostie sides.

2x+8=110

Which is x= 51

For the second one you have supplementray angles

Now for supplementary angles its basically 2 angles added up that form a straight line And 180 degress is always the measure of a straight line. SO in this case we do

9x+12x+75=180

Which is x=5

This is also a vertical angle pair and their congruent just like #1

So 5x+5=65

x=12

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Step-by-step explanation:

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3 years ago

Simplify the expression (3 - 4i)(1 + 5i) - (2 - i). Show your work please! I have the answer: 21 + `12i but I need to show my wo

masha68 [24]

Answer:

21+12i i hope this will help you

Step-by-step explanation:

(3-4i)(1+5i)-(2-i)

=[3(1+5i)-4i(1+5i)]-(2-i)

=[3+15i-4i-20i²]-(2-i)

=(3+11i-20i²)-(2-i)

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3 years ago

A survey was conducted that asked 1003 people how many books they had read in the past year. Results indicated that x overbar eq

Sergio [31]

Answer:

The 99% confidence interval would be given (11.448;14.152).

Step-by-step explanation:

1) Important concepts and notation

A confidence interval for a mean "gives us a range of plausible values for the population mean. If a confidence interval does not include a particular value, we can say that it is not likely that the particular value is the true population mean"

$s=16.6$ represent the sample deviation

$\bar X=12.8$ represent the sample mean

n =1003 is the sample size selected

Confidence =99% or 0.99

$\alpha=1-0.99=0.01$ represent the significance level.

2) Solution to the problem

The confidence interval for the mean would be given by this formula

$\bar X \pm z_{\alpha/2} \frac{s}{\sqrt{n}}$

We can use a z quantile instead of t since the sample size is large enough.

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.