An apartment cost $870 per month to rent. The owner raises the price by 20% and then gives a discount of 8% to returners who sig
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Answer:
The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
A sample of 65 students from the freshmen class is used and a mean score of 76% correct is obtained.
This means that
99% confidence level
So , z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
0.6236*100 = 62.36%
0.8964*100 = 89.64%
The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).
Answer: 6 triangles
Step-by-step explanation:
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Answer:
The conditions for use of the normal model to represent the distribution of sample proportion are not met. He should increase the sample size until the conditions are met.
If the test is done anyway, the null hypothesis failed to be rejected.
The conclusion is taht there is not enough evidence to support the claim that the percentage is lower in this district.
Step-by-step explanation:
The conditions for use of the normal model to represent the distribution of sample proportion are not met, as the affirmative responses are less than 10.
If the test of hypothesis is done as if the conditiones were met, we know that the claim is that the percentage is lower in this district.
Then, the null and alternative hypothesis are:
The significance level is 0.05.
The sample has a size n=80.
The sample proportion is p=0.1.
The standard error of the proportion is:
Then, we can calculate the z-statistic as:
This test is a left-tailed test, so the P-value for this test is calculated as:
As the P-value (0.057) is greater than the significance level (0.05), the effect is not significant.
The null hypothesis failed to be rejected.
There is not enough evidence to support the claim that the percentage is lower in this district.