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Fynjy0 [20]
3 years ago
7

Olivia is making scarves. Each scarf will have 3 rectangle, and 2/3 of the rectangles will be purple. How many purple rectangles

she need for 2 scarves.
Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
6 0

Answer:

she will use 4.

Step-by-step explanation:

kajsbsbsjajaja

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What is m∠PQR? please help
leva [86]

Answer:

127

Step-by-step explanation:

The angles add up to 180° since they are on a straight line. Find 3x - 5.

3x - 5 + x + 1 = 180

4x - 4 = 180

4x = 180 - 4

    = 176

x = 176 ÷ 4

x = 44

3x - 5 = 3(44) - 5

          = 132 - 5

          = 127

6 0
3 years ago
Read 2 more answers
What is the solution to the system of equations
FromTheMoon [43]

Answer:

(0,3)

Step-by-step explanation:

solve for 2y

-X-2y= -6

2y=6+2x

substitute the given value of 2y into the equation -x-2y=-6

-x-(6+3x)= -6

solve for x

x=0

substitute the given value of X into the equation 2y=6+3x

2y=6+3×0

solve for y

y=3

the solution is (0,3)

8 0
3 years ago
Write an equation in slope-intercept form for the line perpendicular to y = -4x + 2 that passes through the point (–5, 2).​
cricket20 [7]

Answer:

y = 5 /2 x − 2

Step-by-step explanation:

The slope-intercept form of a linear equation is:  y = m x + b   Where  m  is the slope and  b  is the y-intercept value.

6 0
3 years ago
Jamal went to the post office to buy stamps and large envelopes. Each stamp costs the same amount, and each large envelope costs
nekit [7.7K]

Answer:

Step-by-step explanation:

i chose .95 cents!

6 0
3 years ago
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
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