I’ll check it give me a minute I’m mainly writing this so I know to come to this just sec
Answer:
Dont knowwwww
Step-by-step explanation:
X + (x + 1) + (x + 2) + (x + 3) = -26
Even though it says negative, the same rules apply.
4x + 6 = -26
4x = -32
x = -8
-8, -7, -6, -5
Hope this helps!
Answer:
10x . . . . . (Note the sign of the middle term is negative. 10x goes in the box.)
Step-by-step explanation:
The sum of the two roots is ...
... (5 -3i) +(5 +3i) = 10
In a quadratic with leading coefficient 1, the coefficient of the 1st-degree term is the opposite of the sum of the roots. Here, that means the middle term is -10x. The minus sign is given, so the answer is 10x.
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<em>How Do We Know?</em>
When "a" and "b" are roots of a quadratic in x, it has factors (x -a)(x -b). The product of those two factors is ...
... (x -a)(x -b) = x² -(a+b)x +ab
Here, that means the product of the factors (5 -3i)(5 +3i) is ab = 34, which it is. Their sum is (a+b) = 10, so the x-term is -(a+b)x = -10x.
Answer:
one solution, no solution, infinitely many solutions
Step-by-step explanation:
I rearranged the first equation into x=6-2y
plug that into the second equation
2(6-2y)-3y=26
12-4y-3y=26
12-7y=26
-7y=14
y=-2
Then you plug that into one of the equations
x+2(-2)=6
x-4=6
x=10
The solution to the first system is (10,-2)
the second system already has one equation as something equal to a single variable so you just plug that into the other one
4x-2(2x-4)=-6
4x -4x +8 =-6
8=-6
this is a false statement so the system of equation has no solution
Lastly I rearranged the first equation into y=2x-4 and then plug that in
6x-3(2x-4)=12
6x-6x+12=12
12=12
this statement is true so the system of equations has infinite solutions
