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What is the y-intercept of the quadratic function f(x) = (x – 8)(x + 3)? (8,0) (0,3) (0,–24) (–5,0)

DiKsa [7]

The correct answer is: [C]: " (0, 24) " .
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Explanation:
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Given the quadratic function:
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→ " y = (x − 8) (x + 3) " ; ← Note: Replace the "f(x)" with: "y" ;

→ Find the "y-intercept".
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→ Note: The "y-intercept" is the coordinate of the point(s) of the graph of the equation at which the graph crosses the "x-axis" when "x = 0" .

→ So; we set plug in "0" for "x" into our equation; and solve for "y" ;

 → " y = (x − 8) (x + 3) " ;

 → y = (0 − 8) (0 + 3) ;

 → y = (-8) * (3) ;

 → y = - 24 ;
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So, the "y -intercept" of the given quadratic function is:

the point at which: "x = 0 ; y = -24 " ;

→ that is; the point the coordinates: " (0, - 24) " ;
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→ which is: Answer choice: [C]: " (0, - 24) " .
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9 0

3 years ago

Read 2 more answers

Find m of ZX in circle P. 70 95 155 205

denis-greek [22]

The answer is C. 155

First find the measure of arc YZ.

The arc of WYZ is equal 180 degrees. So first add 25 to 85. Then subtract that to 180.

25+85=110

180-110=70.

Next add 70 to 85 since you want to find the measure of ZX.

70+85=155

So measure of ZX is equal to 155 degrees

3 0

3 years ago

If anyone could help me it would be deeply appreciated!

Hunter-Best [27]

Answer

-i sqrt 37

Step-by-step explanation:

7 0

3 years ago

Cory went to the fair. He brought $15 with him. The entrance ticket was $4.00. Each ride ticket cost him $ 1.25. Type and solve

nevsk [136]

Answer:

https://www.ringgold.org/cms/lib/PA01916235/Centricity/Domain/227/Algebra%20I%20Keystone%20Review%20Packet%20Answer%20Key.pdf

there you go just a copy and a paste

7 0

3 years ago

in a random sample of 200 people, 154 said that they watched educational television. fine the 90% confidence interval of the tru

melisa1 [442]

Answer:

[0.7210,0.8189] = [72.10%, 81.89%]

Step-by-step explanation:

The sample size is

n = 200

the proportion is

p = 154/200 = 0.77

Since both np ≥ 10 and n(1-p) ≥ 10

We can approximate this discrete binomial distribution with the continuous Normal distribution. As the sample size is large enough, not applying the continuity correction factor makes no significant difference.

The approximation would be to a Normal curve with this parameters:

Mean

p = 0.77

Standard deviation

$\bf s=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.77*0.23}{200}}=0.0298$

The 90% confidence interval for the proportion would be then

$\bf [0.77-z^*0.0298, 0.77+z^*0.0298]$

where $\bf z^*$ is the 10% critical value for the Normal N(0,1) distribution , this is a value such that the area under the N(0,1) curve outside the interval $\bf [-z^*,z^*]$ is 10%=0.1

We can either use a table, a calculator or a spreadsheet to get this value.

In Excel or OpenOffice Calc we use the function

NORMSINV(0.95) and we get a value of 1.645

The 90% confidence interval for the proportion is then

$\bf [0.77-1.645^*0.0298, 0.77+1.645^*0.0298]=[0.7210,0.8189]$

This means there is a 90% probability that the proportion of people who watch educational television is between 72.10% and 81.89%

If the television company wanted to publicize the proportion of viewers, do you think it should use the 90% confidence interval?

Yes, I do.

5 0

3 years ago