Question

Which probability distribution table corresponds with this frequency distribution table

Answer 1

Answer:

A.

$\begin{array}{cccccc}x&1&2&3&4&5\\f&0.2&0.3&0.05&0.2&0.25\end{array}$

Step-by-step explanation:

First find the sum

$\sum f=4+6+1+4+5=20.$

Now, find the probabilities:

• $Pr(x=1)=\dfrac{4}{20}=\dfrac{1}{5}=0.2;$
• $Pr(x=2)=\dfrac{6}{20}=\dfrac{3}{10}=0.3;$
• $Pr(x=3)=\dfrac{1}{20}=0.05;$
• $Pr(x=4)=\dfrac{4}{20}=\dfrac{1}{5}=0.2;$
• $Pr(x=5)=\dfrac{5}{20}=\dfrac{1}{4}=0.25.$

Hence, the frequency distribution table is

$\begin{array}{cccccc}x&1&2&3&4&5\\f&0.2&0.3&0.05&0.2&0.25\end{array}$