Step-by-step explanation:
Hey there!
Given sequences are; 2 , 13 , 24 , 35 , _ , _ .
Now,
Common difference (d) = 2nd term - 1st term. = 13-2 = 11
When we subtract 1st term from 2nd term we find 11 and when we subtract 2nd term from 3rd term we get 11. This means our common difference is 11.
Now, let's find the nrh term of the sequence.
nth term= a1 + (n-1)d ( <em>a1= 1st term, d= common</em> <em>difference</em>)
nth = 2+ (n-1) 11
= 2 + 11n - 11
= 11n - 9
Let's check if we have got nth term correct.
a1= 1*11 - 9 = 2
a2 = 2*11-9 = 13
a3 = 3*11 - 9 = 24
a4 = 4*11-9 = 35
So, we got our nth term.
Let's find remaining sequence.
a5= 5*11 - 9 = 46.
a6= 6*11 - 9 = 57.
Therefore, the remaining terms are : 46 and 57.
<em><u>Hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
The answer would be : 18.0
Hope this helps !
Photon
Hi there
Annual yield=annual interest÷bond cost
Annual interest=1,000×0.06=60
Bond cost=1,000×0.805=805
So
Annual yield=60÷805=0.0745×100
=7.45%
Good luck!
Speed of the east bound cyclist is 12 mph and the speed of west bound cyclist is 15 mph.
<u>Solution:</u>
Let us assume that x is speed of slower eastbound cyclist
So, x+3 will be the speed of faster westbound cyclist
We know that distance is the product of speed and time. That is,
West-bound DATA:
Rate of speed = x+3 mph ; Time = 6 hrs ; distance = 6(x+3) = 6x+18 miles
East-bound DATA:
Rate of speed = x mph ; time = 6 hrs. ; distance = 6x miles
On solving,
Distance apart = 162
So, the rate of speed of the east bound cyclist is 12 mph and the rate of speed of the west bound cyclist will be 
Answer:1/12
Step-by-step explanation:
