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3 years ago

PLZZ HELP!! LAST QUESTION ON MY TEST!! Is the graph linear or non-linear? Explain your answer.

Mathematics

2 answers:

timurjin [86]3 years ago

8 0

Answer:

non linear. its not a straight line. it has curves and breaks.

Step-by-step explanation:

Nimfa-mama [501]3 years ago

6 0

Answer:

Non linear ofc

Linear = straight line

The line on the graph is not straight

Step-by-step explanation:

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Order the following numbers from least to greatest<br> numbers:1 8/25,1.3,5/4

Brut [27]

Answer:

i think it 5/4, 3.1, 1 8/25

Step-by-step explanation:

let me know if its right

8 0

3 years ago

Solve using the standard algorithm <br> 1.03 +0.08

nataly862011 [7]

Answer:

1.11

Step-by-step explanation:

1.03+0.08=1.11

4 0

3 years ago

Deer ticks can be carriers of either Lyme disease or human granulocytic ehrlichiosis (HGE). Based on a recent study, suppose tha

san4es73 [151]

Answer:

0.2364

Step-by-step explanation:

We will take

Lyme = L

HGE = H

P(L) = 16% = 0.16

P(H) = 10% = 0.10

P(L ∩ H) = 0.10 x p(L U H)

Using the addition theorem

P(L U H) = p(L) + P(H) - P(L ∩ H)

P(L U H) = 0.16 + 0.10 - 0.10 * p(L u H)

P(L U H) = 0.26 - 0.10p(L u H)

We collect like terms

P(L U H) + 0.10P(L U H) = 0.26

This can be rewritten as:

P(L U H)[1 +0.1] = 0.26

Then we have,

1.1p(L U H) = 0.26

We divide through by 1.1

P(L U H) = 0.26/1.1

= 0.2364

Therefore

P(L ∩ H) = 0.10 x 0.2364

The probability of tick also carrying lyme disease

P(L|H) = p(L ∩ H)/P(H)

= 0.1x0.2364/0.1

= 0.2364

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=f%28x%29%20-%20%5Cfrac%7Bx%5E%7B2%7D-4%20%7D%7Bx%5E%7B4%7D%20%2Bx%5E%7B3%7D%20-4x%5E%7B2%7D-4%

Llana [10]

a) The given function is

$f(x)=\frac{x^2-4}{x^4+x^3-4x^2-4}$

The domain refers to all values of x for which the function is defined.

The function is defined for

$x^4+x^3-4x^2-4\ne0$

This implies that;

$x\ne -2.69,x\ne 1.83$

b) The vertical asymptotes are x-values that makes the function undefined.

To find the vertical asymptote, equate the denominator to zero and solve for x.

$x^4+x^3-4x^2-4=0$

This implies that;

$x= -2.69,x=1.83$

c) The roots are the x-intercepts of the graph.

To find the roots, we equate the function to zero and solve for x.

$\frac{x^2-4}{x^4+x^3-4x^2-4}=0$

$\Rightarrow x^2-4=0$

$x^2=4$

$x=\pm \sqrt{4}$

$x=\pm2$

The roots are $x=-2,x=2$

d) The y-intercept is where the graph touches the y-axis.

To find the y-inter, we substitute;

$x=0$ into the function

$f(0)=\frac{0^2-4}{0^4+0^3-4(0)^2-4}$

$f(0)=\frac{-4}{-4}=1$

e) to find the horizontal asypmtote, we take limit to infinity

$lim_{x\to \infty}\frac{x^2-4}{x^4+x^3-4x^2-4}=0$

The horizontal asymtote is $y=0$

f) The greatest common divisor of both the numerator and the denominator is 1.

There is no common factor of the numerator and the denominator which is at least a linear factor.

Therefore the function has no holes.

g) The given function is a proper rational function.

There is no oblique asymptote.

See attachment for graph.

6 0

3 years ago

Given f(x)=2x2-3, find F(-3)

Paraphin [41]

Answer:

f(-3) = 15

Step-by-step explanation:

f(x)= 2x^2 - 3

Plug in x = -3 into the function

f(-3) = 2(-3)^2 - 3

f(-3) = 18 - 3

f(-3) = 15

3 0

3 years ago

Read 2 more answers