Answer:
p = 
and q = 
Step-by-step explanation:
Given equations:
2p - 3q = 4 -----------(i)
3p + 2q = 9 ------------(ii)
Let's solve this equation simultaneously using the <em>elimination method</em>
(a) Multiply equation (i) by 3 and equation (ii) by 2 as follows;
[2p - 3q = 4] x 3
[3p + 2q = 9] x 2
6p - 9q = 12 -------------(iii)
6p + 4q = 18 -------------(iv)
(b) Next, subtract equation (iv) from equation (iii) as follows;
[6p - 9q = 12]
<u> - [6p + 4q = 18] </u>
<u> -13q = -6 </u> -----------------(v)
<u />
<u>(c)</u> Next, make q subject of the formula in equation (v)
q =
(d) Now substitute the value of q = into equation (i) as follows;
2p - 3() = 4
(e) Now, solve for p in d above
<em>Multiply through by 13;</em>
26p - 18 = 52
<em>Collect like terms</em>
26p = 52 + 18
26p = 70
<em>Divide both sides by 2</em>
13p = 35
p =
Therefore, p = and q =
Answer:
n-17
Step-by-step explanation:
Answer:
-tan80°
Step-by-step explanation:
Answer:
226.084 sq.m.
Step-by-step explanation:
Radius of circle = 18.6 cm
Area of sector = 
Area of sector = 
Area of sector = 
Area of triangle = 
a = OA = radius = 18.6 cm
b = OB = radius = 18.6 cm
x =123 °
Substitute the values in the formula
Area of triangle = 
Area of triangle = 
So, Area of shaded region = Area of sector - Area of triangle
=
=
Hence the area of the shaded region is 226.084 sq.m.
I don't see a drawing of the quadrilaterals, so I don't know what the perimeter of quadrilateral P is. But whatever the perimeter of P is, Q will be 1/3 of that. Perimeter is a length, so even though it may pertain to a 2-dimensional object, it is still a 1-dimensional, linear measure. When two objects are similar (same shape, but scaled up or down by a scale factor), all corresponding linear measures have the same scale factor.
If you were asked about area or volume, that would be a different matter. In the case of area, you would square the scale factor, and in the case of volume, you would cube the scale factor.
