Answer:
Step-by-step explanation:
We are solving for 
in the equation:
First, isolate the variable term by subtracting 
from both sides of the equation:
Now, divide both sides of the equation by the coefficient of :
This solution for , as a decimal, would be non-terminating. If you divided 
into 
, you would get the non-terminating decimal of:
Therefore, our solution is:
-
We can check our solution by substituting 
for in the initial equation:
Substitute:
Simplify 
:
Add:
Since both sides of the equation are equal, our solution is correct!
![\large\begin{array}{l} \textsf{Therefore, the domain of f is}\\\\ \mathsf{D_f=\{x\in\mathbb{R}:~~x\ne -7~~and~~x\ne 7\}}\\\\\\ \textsf{or using a more compact form}\\\\ \mathsf{D_f=\mathbb{R}\setminus\{-7,\,7\}}\\\\\\ \textsf{or using the interval notation}\\\\ \mathsf{D_f=\left]-\infty,\,-7\right[\,\cup\,\left]7,\,+\infty\right[.} \end{array}](https://tex.z-dn.net/?f=%5Clarge%5Cbegin%7Barray%7D%7Bl%7D%20%5Ctextsf%7BTherefore%2C%20the%20domain%20of%20f%20is%7D%5C%5C%5C%5C%20%5Cmathsf%7BD_f%3D%5C%7Bx%5Cin%5Cmathbb%7BR%7D%3A~~x%5Cne%20-7~~and~~x%5Cne%207%5C%7D%7D%5C%5C%5C%5C%5C%5C%20%5Ctextsf%7Bor%20using%20a%20more%20compact%20form%7D%5C%5C%5C%5C%20%5Cmathsf%7BD_f%3D%5Cmathbb%7BR%7D%5Csetminus%5C%7B-7%2C%5C%2C7%5C%7D%7D%5C%5C%5C%5C%5C%5C%20%5Ctextsf%7Bor%20using%20the%20interval%20notation%7D%5C%5C%5C%5C%20%5Cmathsf%7BD_f%3D%5Cleft%5D-%5Cinfty%2C%5C%2C-7%5Cright%5B%5C%2C%5Ccup%5C%2C%5Cleft%5D7%2C%5C%2C%2B%5Cinfty%5Cright%5B.%7D%20%5Cend%7Barray%7D)
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Tags: <em>function domain real rational factorizing special product interval</em>
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X= -2 and x=0
I'll explain it to you if you want
Answer: a=51
Step-by-step explanation:
