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hammer [34]
2 years ago
12

Please solve the table and show your work

Mathematics
1 answer:
Elanso [62]2 years ago
3 0

Answer:

a

Step-by-step explanation:

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SV is a midsegment of △RTU.<br> If TU=y+38 and SV=y–9, what is the value of y?
pav-90 [236]

Answer:

y = 56

Step-by-step explanation:

the midsegment SV is half the length of the side TU , that is

y - 9 = \frac{1}{2} (y + 38) ← multiply both sides by 2 to clear the fraction

2y - 18 = y + 38 ( subtract y from both sides )

y - 18 = 38 ( add 18 to both sides )

y = 56

8 0
2 years ago
If the length of a rectangle is three times it’s width and it’s parameter is 24cm what is the area
katrin [286]

Answer:

Area = 27 cm²

Step-by-step explanation:

let L be the length of the rectangle

    w the width

    P the perimeter

    A the area

<u>Formulas</u> :

P = 2×(L + w)

A = L × w

<u>We are Given</u> :

L = 3w

P = 2×(L + w)

⇔ 24 = 2×(3w + w)

⇔ 24 = 2×4w

⇔ 24 = 8w

⇔ w = 24/8 = 3

Then

L = 3w = 3×3 = 9

We obtain L = 9 and w = 3.

Then

A = L × w

  = 9 × 3

  = 27

6 0
2 years ago
the maximum distance D in kilometers that you can see from a height H in meters is given by the formula d equals 3.5 times the s
Irina-Kira [14]
First put the words in an algebraic format or a model. D = 3.5(√H). Now determine what the question is asking. It's height. Plug in the value of D. Distance is 35 km.
35 = 3.5(√H) We want to get H by itself. First thing to get away from it is 3.5. So                      divide 35 by 3.5 And 3.5(√h) by 3.5.
10 = √H        To get rid of √ do the opposite raise to the power of 2
10² = (√H)²   
100 = H 
You must be 100 kilometers above ground to see 35 kilometers

7 0
3 years ago
If a simple machine reduces the strength of a force, what must be increased?
ch4aika [34]
I think the answer is C.  The distance over which the force is applied. Hope this helps!
4 0
2 years ago
What is number 20 simplified?
guapka [62]

Answer:

  2

----------

5w^11


Step-by-step explanation:

8/20 reduces to 2/5, and (w^(-2)) / w^9 becomes 1 / w^11.

Overall, #20 reduces to:

  2

----------

5w^11


Recall the rule of exponents:

  w^a

----------- = w^(a-b)

  w^b


and note that

 w^(-2)

------------ = w^(-2-9)  =  w^(-11) (same as above)

  w^9

6 0
3 years ago
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