Answer:
420.72
Step-by-step explanation:
Answer:

Step-by-step explanation:
Let the equation of the perpendicular line is,
y = mx + b
where m = slope of the line
b = y-intercept
From the graph, slope of the line passing through (0, -1) and (3, 1),
m' =
m' = 
m' = 
To get the slope (m) of this line we will use the property of perpendicular lines,
m × m' = (-1)
m ×
= -1
m = 
Equation of the perpendicular line will be,

x-intercept of the line is (-3) therefore, point on the line is (-3, 0)
0 = 
b = 
Equation of the line will be,

A straight line is 180°. 180°-135°=55°, so x=55°, which is an acute angle because it is less than 90°.
Answer:ʜᴛᴛᴘꜱ://ᴡᴡᴡ.ʏᴏᴜᴛᴜʙᴇ.ᴄᴏᴍ/ᴡᴀᴛᴄʜ?ᴠ=ᴅQᴡ4ᴡ9ᴡɢxᴄQ
Step-by-step explanation:
Heres the answer but its on a another page.
Im joking
here's the answer
the first one is 878 i think that what your looking for at the top
Answer:
78º
Step-by-step explanation:
<u>Note</u> : -
In mathematics, the reference angle is defined as the acute angle and it is measuring less than 90 degrees. It is always the smallest angle, and it makes the terminal side of an angle with the
x - axis.
<u>S</u><u>t</u><u>e</u><u>p</u><u> </u><u>1</u> : -
Find where 192º lies in which quadrant.
192º lies in 3rd quadrant ( between
180º and 270º )
<u>S</u><u>t</u><u>e</u><u>p</u><u> </u><u>2</u> : -
Subtract : 270 - 192
270 - 192 = 78º
( Since, 192º is greater than 180º, is subtracted from 270º )
<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u> : -
78º is the reference angle for 192º.