Area of the figure = 112 in²
Solution:
The given figure is splitted into two shapes.
One shape is square.
Each side of square are equal.
Side = 10 inch
Area of the square = side × side
= 10 × 10
= 100
Area of the square = 100 in²
The other shape is triangle.
Base of the triangle = 10 in – 6 in = 4 inch
Height of the triangle = 16 in – 10 in = 6 inch
Area of the triangle = 
= 12
Area of the triangle = 12 in²
Area of the figure = Area of the square + Area of the triangle
= 100 in² + 12 in²
Area of the figure = 112 in²
Therefore, area of the given figure is 112 in².
The coterminal angle for the -4π/5 are -14π/5 , 6π/5 and reference angle is π/5 respectively.
<h3>What is coterminal angles?</h3>
Two different angles that have the identical starting and ending edges termed coterminal angles however, since one angle measured clockwise and the other determined counterclockwise, the angles' terminal sides have completed distinct entire rotations.
We have an angle:
-4π/5
To find the coterminal angle, add and subtract by 2π in the angle -4π/5
Coterminal angle:
= -4π/5 - 2π
= -14π/5
= -4π/5 + 2π
= 6π/5
Reference angle:
= π - 4π/5 (as the angle lies in the second quadrant)
= π/5
Thus, the coterminal angle for the -4π/5 are -14π/5 , 6π/5 and reference angle is π/5 respectively.
Learn more about the coterminal angles here:
brainly.com/question/23093580
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Answer:
(C)4
Step-by-step explanation:
Given the line: 
The gradient of the line, 
A line perpendicular to the given line will have a gradient, 
(by definition of perpendicularity).
Therefore, a perpendicular line that passes through the point (4,1) is:
Comparing with the slope-intercept form y=mx+x, the slope of the perpendicular line, b=4.
