Answer:
Step-by-step explanation:
Given that a confidence interval was constructed using the sample standard deviation, say CI-1.
We then construct a confidence interval with the same numerical values of sample mean, standard deviation, and sample size, but this time assuming the population standard deviation is known, say CI-2.
When population std dev is known we use std error =
For sample std deviation s, we use std error =
When s= sigma, there will not be any difference between these two confidence intervals.
So answer is equal.
Answer:
No, it can not be applied.
Step-by-step explanation:
f(x) = 1/x²
f(x) is a polynomial that is not continuous
As,
f(x) = 1/0 is undefines
Secondly, it is not differentiable (i.e. the derivative does not exists on the interval given)
Derivative of this function
f'(x) = (1)x^-2
= -2x^(-2-1)
= -2x^(-3)
= -2/x³
= -2/x³
f'(0) = -2/0 is undefined
Thus, mean value theorem can not be applied.
4.25+13=17.25.
Total is $17.25
Note: Consider the side of first triangle is TQ instead of TA.
Given:
Triangles TQM and TPN which share vertex T.
To find:
The theorem which shows that .
Solution:
In triangle TQM and TPN,
[Given]
[Given]
[Given]
Since two sides and their including angle are congruent in both triangles, therefore both triangles are congruent by SAS postulate.
[SAS]
Therefore, the correct option is C.