Answer:
<em>2.5 hours</em>
<u>Skills needed: Speed, distance, time problems</u>
Step-by-step explanation:
1) We are given speed and distance, and have to find out the the time (in hours).
- In terms of units, everything is matched up (Since distance and speed use kilometers, and speed and time use hours).
- Time is always the distance you travelled (how far) divided by how fast you travelled (the rate/speed)
---> We can use the formula for time: 
t= time
d=distance
r=rate/speed
2) Now, let's plug in for distance and rate.
---> 
2.5 hours is the answer.
Answer:
Perimeter = 6x² + 8x
Step-by-step explanation:
Perimeter = 2(length + width)
perimeter = 2((x²+x)+(2x²+3x))
perimeter = 2(x²+2x² + x+3x)
perimeter = 2(3x² + 4x)
perimeter = 2*3x² + 2*4x
perimeter = 6x² + 8x
Answer:
The 4rth line and 5th line
Step-by-step explanation:
This 2 cup measuring cup with 8 division lines
8th line ------ 2 cups
7th line ------
6th line ------
5th line -----
4th line ----- at this line 1 cup
3rd line -----
2nd line ----
1st line ----
Answer:
785 almonds
Step-by-step explanation:
157 x 5 = 785
A
Volume of the Cylinder
Givens
H = 60 yards.
Diameter = 20 yards
pi = 3.14
Formula
V = pi * r^2 * h
Calculations
r = d/2
r = 32/2
r = 16
V = 3.14 * 16^2 * 60
V = 48230 cubic yards [Cylinder's Volume]
Cone
<em>Formula</em>
V = 1/3 pi r^2 H
<em>Givens</em>
pi = 3.14
r = 16 yards
h = 20 yards
<em>Sub and solve</em>
V = 1/3 3.14 * 16^2 * 20
V = 5359 cubic yards.
<em>Total Volume of the structure</em>
48230 + 5359 = 53589 Cubic Yards
<em>Water Content</em>
The answer to this part requires a proportion.
1 Cubic yard will hold 201.97 gallons.
53589 yd^3 = x
1/201.97 = 53589 /x [ You should get a pretty big answer]
x = 201.87 * 53589
x = 10 819 092 gallons can be held by the tank.
10 819 092 gallons <<<< answer
B
If the height of both the cylinder and the cone remain the same. If the radius doubles in both the cylinder and the cone then the tank will hold 4 times as much.
Total volume before doubling the radius = pi * r^2 h + 1/3 pi r^2 h
New Total Volume = pi * (2*r)^2 h + 1/3 pi * (2r)^2 h
New Total volume = pi * 4r^2 h + 1/3 pi *4 r^2 h
New Total Volume = 4 [pi r^2 h + 1/3 pi r^2 h]
but pi r^2 h + 1/3 pi r^2 h is the total volume before doubling the radius
New volume = 4 original volume. <<<<< answer to part B
