Solution:
Equation of line perpendicular to , x=4 is
y +k=0
As, keep in mind , the equation of line perpendicular to , ax + by +c=0 is b x - a y +c=0
As, given the line perpendicular to, x =4, passes through the point (5,7).
So, y+k =0, passes through (5,7).
→ 7 +k=0
→ k= -7
So, line perpendicular to x=4, which passes through the point (5,7) is →y-7=0 that is y=7.
Option (C) →y=7
