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rosijanka [135]
3 years ago
9

Un microempresario necesita su apoyo para elaborar un plan de crédito con el propósito de colocar entre sus clientes un "paquete

de sala y mesa de centro para el hogar". El plan de crédito consiste en solicitar al cliente un anticipo y el resto de la deuda pagarla en tres pagos mensuales iguales al final de los meses 1, 2 y 3, contados a partir de la fecha en que se entregue el anticipo. El precio de contado del paquete de productos es de $18,500 pesos. Suponiendo una tasa de oportunidad del 18% anual simple, ¿de cuanto seria cada uno de los tres pagos mensuales iguales, si para cerrar el trato se requiere que el cliente cubra un anticipo de $ 3,500?
Mathematics
1 answer:
kvv77 [185]3 years ago
7 0

Answer:

no hablo espanol :/

Step-by-step explanation:

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The back of a large truck can hold 3,560 pounds. If a crate of milk weighs 160 ounces, how many crates will the back of the truc
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if 1 crate is of 10 pounds then 3560 pounds contains 3560/10 crates

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A video sharing website starts with 20,000 members. Each year it loses 25% of the members, but adds 10,000 new members after the
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Which of the following is the inverse of y=12^x
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An instructor in a college class recently gave an exam that was worth a total of 100 points. The instructor inadvertently made t
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Answer:

B) Method 2 will increase the standard deviation of the students' scores.

Step-by-step explanation:

Given that an instructor in a college class recently gave an exam that was worth a total of 100 points.

The average score for his students was 43 and the standard deviation of the scores was 5 points.

And now he is considering two different strategies for rescaling the exam results of which:

Method 1 = Add 17 points to everyone's score.

Method 2 = Multiply everyone's score by 1.7 .

And we have to check what will be the impact of these methods on the standard deviation of the students' scores.

For this let us consider a simple example to understand this:

Firstly, Formula for calculating Standard Deviation =  \sqrt{\frac{\sum (X-Xbar)^{2}}{n-1}}

Suppose,

     X             X - Xbar       (X - Xbar)^{2}

     3              3 - 6 = -3         -3 * -3 = 9

     5              5 - 6 = -1          -1 * -1 = 1

     10            10 - 6 = 4          4 * 4 = 16

<em>Mean of above data, Xbar</em> = \frac{3+ 5+10}{3} = 6

<em>Standard Deviation of data </em>= \sqrt{\frac{26}{3-1} } = 3.6055

Now let us suppose that we multiply each value of above data with 2 so the new data will be:

     X                X - Xbar           (X - Xbar)^{2}

 3*2 = 6        6 - 12 = -6         -6 * -6 = 36

 5*2 = 10       10 - 12 = -2       -2 * -2 = 4

10*2 =20      20 - 12 = 8         8 * 8 = 64

<em>Mean of new data, Xbar </em>= \frac{6+ 10+20}{3} = 12

<em>Standard Deviation of new data</em> = \sqrt{\frac{104}{3-1} } = 7.2111

<em>Hence, we see that when we multiply any value to the data the standard deviation will increase and in other words it will multiplied by that value which value we multiplied with each data value i.e. when we multiply each data value with 2 the standard deviation also get multiplied by as </em>

  3.6055 * 2 = 7.2111

Therefore option B is correct that Method 2 will increase the standard deviation of the students' scores.

<em>And on the other hand Similarly by adding any constant to the data the Standard Deviation will remain same. Therefore Method 1 will have no impact on standard deviation of the students' scores.</em>

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