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kap26 [50]
3 years ago
9

PLEASE HELP!!!! Geometry is so hard and this is due tonight :(

Mathematics
2 answers:
Brut [27]3 years ago
6 0
Sin(62)=x/14
x=14sin(62)
Just use calculator and will get the answer of first question.
Second one ,
Cos(50)=3.5/x
X=3.5/cos(50)
Use calculator and get answer for second
sveticcg [70]3 years ago
5 0

Answer:

<em><u>Its</u></em><em><u> </u></em><em><u>blurrrr</u></em>

<em><u>I</u></em><em><u> </u></em><em><u>can't</u></em><em><u> </u></em><em><u>even</u></em><em><u> </u></em><em><u>see</u></em><em><u> </u></em><em><u>the question</u></em><em><u>!</u></em><em><u>!</u></em><em><u> </u></em>

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What is the difference to the nearest hundredth of a unit between the two zeros
Luda [366]

Answer:

0.1

Step-by-step explanation:

hwhhehhejejeejjrjr

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=3%20%5Csqrt%7B2%7D%20%20-%204%20%20%5Cdiv%20%20%5Csqrt%7B3%7D%20%20-%202" id="TexFormula1" tit
ivann1987 [24]
Simplify the following:
(3 sqrt(2) - 4)/(sqrt(3) - 2)

Multiply numerator and denominator of (3 sqrt(2) - 4)/(sqrt(3) - 2) by -1:
-(3 sqrt(2) - 4)/(2 - sqrt(3))

-(3 sqrt(2) - 4) = 4 - 3 sqrt(2):
(4 - 3 sqrt(2))/(2 - sqrt(3))

Multiply numerator and denominator of (4 - 3 sqrt(2))/(2 - sqrt(3)) by sqrt(3) + 2:
((4 - 3 sqrt(2)) (sqrt(3) + 2))/((2 - sqrt(3)) (sqrt(3) + 2))

(2 - sqrt(3)) (sqrt(3) + 2) = 2×2 + 2 sqrt(3) - sqrt(3)×2 - sqrt(3) sqrt(3) = 4 + 2 sqrt(3) - 2 sqrt(3) - 3 = 1:
((4 - 3 sqrt(2)) (sqrt(3) + 2))/1

((4 - 3 sqrt(2)) (sqrt(3) + 2))/1 = (4 - 3 sqrt(2)) (sqrt(3) + 2):
Answer: (4 - 3 sqrt(2)) (sqrt(3) + 2)
4 0
3 years ago
Please somebody else help me to do . I will mark the correct answer as a brainiest​
vodomira [7]

there is your answer follow and mark me as <em><u>brainliest </u></em>

4 0
3 years ago
On a number line, the directed line segment from Q to S has endpoints Q at -2 and S at 6. Point R partitions the directed line s
Alona [7]
The answer is 14/5, there ya go
7 0
3 years ago
Read 2 more answers
A square pyramid has base edge length 14 m. The height of the pyramid is 24 m. Find the surface area of the square pyramid. Use
kotegsom [21]

Answer:

The total surface area is 896 m^{2}

Step-by-step explanation:

<em>The square pyramid is a solid with square base and symmetric 4 triangular faces.</em>

Given that the square base is 14 m and height is 24 m.

The apex of pyramid, center of square and center of any edge of square make a right angled triangle.

Let that height if triangular face be "x".

by pythagoras theorm , x^{2} = 7^{2} + 24^{2} = 625

x = 25 m

the area of square base is 14^{2} = 196 m^{2}

the area of each triangular side is <em>(\frac{1}{2})(base)(height) = (\frac{1}{2})(14)(25) = 135 m^{2}</em>

such are 4 triangles, thus (4)(135) = 700 m^{2}

Thus the total surface area is 196 + 700 = 896 m^{2}

8 0
3 years ago
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